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aivan3 [116]
2 years ago
8

Stefanie is three times as old as Hannah. Four years ago, the sum of their ages was 28. How old are they now? Be sure to define

your variable(s)
Mathematics
1 answer:
siniylev [52]2 years ago
4 0

Stefanie's age is 54 and Hannah's age is 18

<h3>How to determine their current ages?</h3>

Let x represent Stefanie's age and y represent Hannah's age

<u>Presently</u>

x = 3y

<u>Four years ago</u>

x - 4 + y - 4 = 28

Substitute x = 3y in the above equation

3y - 4 + y - 4 = 28

Evaluate the like terms

2y = 36

Divide both sides by 2

y = 18

Substitute y = 18 in x = 3y

x = 3 * 18

Evaluate

x = 54

Hence, Stefanie's age is 54 and Hannah's age is 18

Read more about equations at:

brainly.com/question/2972832

#SPJ1

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Steven lives 1500 yards from the corner store, and 2700 yards from the park. the park, the store, and steves house are all colli
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Answer:

4200

Step-by-step explanation:

Just add both distances together since we know his house is in between both the shop and the park.

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1 year ago
Five carpenters worked 15 &amp; 3/4, 15 &amp; 1/4, 17 &amp; 1/2, 12 &amp; 1/2 and 17 &amp; 1/2 hours respectively. What was the
azamat

<u>The total </u><u>labor cost</u><u>  of the carpenters is $2296.91</u>

The carpenters worked 15\frac{3}{4} , 15\frac{1}{4}, 17\frac{1}{2}, 12\frac{1}{2}, 17\frac{1}{2}

<h3>Conversion of Fraction</h3>

Let's convert the mixed fraction to improper fraction

So, we would have

  • 63/4,
  • 61/4,
  • 35/2,
  • 25/2
  • 35/2.
<h3>Working Cost</h3>

Let's sum it up and multiply by the working cost per hour

63/4 + 61/4 + 35/2 + 25/2 + 35/2 =78.5

  • The total labor cost is = total hours worked * hourly rate.

This becomes 78.5*29.26=2296.91

<u>The total labor cost is $2296.91</u>

Learn more about rate here;

brainly.com/question/1115815

3 0
3 years ago
How to solve logarithmic equations as such
Serga [27]

\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5

\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}

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3 years ago
Select all of the options which are examples of expenditure.
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Spending money on a game
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2 years ago
7 hundreds times ten equals
GaryK [48]


70 is 7 times 10 man

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3 years ago
Read 2 more answers
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