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aivan3 [116]
2 years ago
8

Stefanie is three times as old as Hannah. Four years ago, the sum of their ages was 28. How old are they now? Be sure to define

your variable(s)
Mathematics
1 answer:
siniylev [52]2 years ago
4 0

Stefanie's age is 54 and Hannah's age is 18

<h3>How to determine their current ages?</h3>

Let x represent Stefanie's age and y represent Hannah's age

<u>Presently</u>

x = 3y

<u>Four years ago</u>

x - 4 + y - 4 = 28

Substitute x = 3y in the above equation

3y - 4 + y - 4 = 28

Evaluate the like terms

2y = 36

Divide both sides by 2

y = 18

Substitute y = 18 in x = 3y

x = 3 * 18

Evaluate

x = 54

Hence, Stefanie's age is 54 and Hannah's age is 18

Read more about equations at:

brainly.com/question/2972832

#SPJ1

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5 0
3 years ago
A charter airline finds that on its Saturday flights from Philadelphia to London, all 120 seats will be sold if the ticket price
Nataliya [291]

Answer:

a) P=3(120-s)+200

b) 215 \leq P \leq 290

Step-by-step explanation:

For this case we can use a linear model to solve the problem.

s) Create an equation to express the increase on the price tickets and the number of seats sold

s number of seats, if w analyze the info given the number of seats after increase the price is given by 120-s.

And let P the price for the ticket. So after the increase in ticket price the expression for the increase is P-200.

We have an additional info, for each increase of $3 the number of setas decrease 1. And the equation that gives to us the price change in terms of the increase of price is:

P-200=3(120-s)

So then our linear equation is given by:

P=3(120-s)+200

b) Over a certain period, the number of seats sold for this flight ranged between 90 and 115. What was the corresponding range of ticket prices?

So for this case we just need to replace the limits into the linear equation and see what we got:

P_L=3(120-90)+200=290

P_U=3(120-115)+200=215

So the corresponding range of ticket prices is:

215 \leq P \leq 290

4 0
2 years ago
Please help me with it is for homework<br><br> I really need help please help me
Solnce55 [7]

Answer:

See explanation

Step-by-step explanation:

Given two expressions:

2(s+0.5)+2(s+1.5)

and

4\left(\dfrac{1}{2}s+\dfrac{1}{4}s\right)+4

a. When s=0,

then

2(s+0.5)+2(s+1.5)=2(0+0.5)+2(0+1.5)=1+3=4

and

4\left(\dfrac{1}{2}s+\dfrac{1}{4}s\right)+4=4\left(\dfrac{1}{2}\cdot 0+\dfrac{1}{4}\cdot 0\right)+4=4

b. When s=12,

then

2(s+0.5)+2(s+1.5)=2(12+0.5)+2(12+1.5)=2\cdot 12.5+2\cdot 13.5=25+27=52

and

4\left(\dfrac{1}{2}s+\dfrac{1}{4}s\right)+4=4\left(\dfrac{1}{2}\cdot 12+\dfrac{1}{4}\cdot 12\right)+4=4(6+3)+4=4\cdot 9+4=36+6=40

c. Since the value of both expressions at s = 12 are different, the expressions are not equivalent.

6 0
3 years ago
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