Answer:
131 1/4 in.²
Step-by-step explanation:
To find the area of the figure, you would have to divide the figure into two parts. The figure can be divided into two rectangles.
<u>Rectangle 1</u>
The length is 11 3/4 in. The width is 6 in.
A = lw
A = (11 3/4 in.)(6 in.)
A = 70 1/2 in.²
<u>Rectangle 2</u>
The length is 9 in. The width is 6 3/4 in.
A = lw
A = (9 in.)(6 3/4 in.)
A = 60 3/4 in.²
Add the two areas together.
70 1/2 in.² + 60 3/4 in.² = 131 1/4 in.²
Answer:
-1/4x² + 3
Step-by-step explanation:
Given that:
Path of sprinkler is modeled by the quadratic function :
w(x) = -1/4(x^2 -12 )
w(x) = height of the water, in meters, at position x
The height of ceiling as a constant or Coefficient = w(x)
Expanding w(x)
-1/4(x^2 -12 )
-1/4 * x² + 1/4 * 12
-1/4x² + 3
The height of ceiling is -1/4x² + 3
Answer and Step-by-step explanation:
Considering the table attached.
(a) over 9.5 kg;
μ = 8
σ = 0.9
z = 9.5 - 8/0.9 ≈ 1.67
P (Z > 1.67) = 0.5 - P(0<Z<1.67) = 0.5 - 0.4525 = 0.0475
(b) at most 8.6 kg;
z = 8.6-8/0.9 ≈ 0.67
P(Z < 0.67) = 0.5 + P(0<Z<0.67) = 0.5 + 0.2486 = 0.7486
(c) between 7.3 and 9.1 kg.
z₁ = 7.3-8/0.9 ≈ -0.78
z₂ = 9.1 - 8/0.9 ≈ 1.22
P(-0.78 < Z < 1.22) = P(0 < Z < 0.78) + P(0 < Z < 1.22) = 0.2823 + 0.3888 = 0.6711