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Maksim231197 [3]
3 years ago
12

A forest fire covers 2006 acres at time t equals 0. the fire is growing at a rate of 8 startroot t endroot acres per hour, where

t is in hours. how many acres are covered 24 hours later? round your answer to the nearest integer. the total area covered 24 hours later is entry field with incorrect answer 111811 acres. the tolerance is +/-2% click if you would like to show work for this question: open show work
Mathematics
1 answer:
MissTica3 years ago
8 0
<span>Answer: We'll have to integrate the growth rate with respect to time, without forgetting the amount of area covered at the start. A = 2010 + â« 8t1/2 dt (as t goes from 0 to 24) A = 2010 + [(16/3) t3/2] (as t goes from 0 to 24) A = 2010 + 627 = 2637 acres We don't integrate the 2010 here because whatever effects of the passing of time have already taken place over that area. We just treat it as a constant and add it to the result of integration.</span>
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Answer:

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3 years ago
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The scale on a map is 55 cm: 88 km. If the distance between two cities is 5656 km, how far apart in cm are the two cities on the
Alinara [238K]

Answer:

3,535 cm

Step-by-step explanation:

55cm=88km

Let's make that "one unit" - 55cm=1 unit. How many units are in the distance 5656km?

5656km/88km=64.2727... units.

55cmx64.2727... = 3,534.999 cm (depending on what your teacher requires, we can probably round to 3,535).

Therefore, we know that the two cities are 3,535 cm apart on the map.

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2 years ago
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Choose the correct equation in point-slope form for the line that passes through the point with the given slope. (2, -1), m= -3
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Y - y1 = m(x - x1)
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3 years ago
Convert 3upon4 in persentage:<br>1. 25%<br>2. 50%<br>3. 1%<br>4. 75%​
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Answer:

75%

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Think of it this way. 3 quarters is 75 cents. It's the same as 3/4, since 4 quarters makes $1.00.

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3 years ago
The velocity of a car over five hours is given by v(t)=60ln(t+1),0≤t≤5 in kilometers per hour. What is the total distance travel
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Step-by-step explanation:

as the velocity is not constant over time, we actually have to integrate v(t) over the interval 0<=t<=5 to get the distance.

v(t) = 60×ln(t + 1)

V(t) = 60 × integral(ln(t + 1)) between 0 and 5.

integral(ln(t + 1)) = (t + 1)ln(t + 1) - t + C

V(t) = 60 × ((t + 1)ln(t + 1) - t + C)

the distance traveled between t = 0 and t = 5 is then

60 × ((5 + 1)ln(5 + 1) - 5 + C) - 60 × ((0 + 1)ln(0 + 1) - 0 + C) =

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2 years ago
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