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Paha777 [63]
2 years ago
7

Solve for x {x+4]= 6

Mathematics
2 answers:
elena-14-01-66 [18.8K]2 years ago
7 0

Answer:

Step-by-step explanation:

Always do opposite. E.g, opposite of square is square root.

x(x + 4) = 6

expand brackets

x^2 + 4 = 6

minus 4 from both sides

x^2 = 6 - 4

square root everything

x = \sqrt{6-4}

wlad13 [49]2 years ago
6 0

The solution to the equation x(x+4) = 6 is x = -2 + √10 or x = -2 - √10 after solving with the quadratic formula.

<h3>What is a quadratic equation?</h3>

Any equation of the form \rm ax^2+bx+c=0 where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}

We have an equation:

x(x + 4) = 6

By distributive property:

x² + 4x = 6

x² + 4x - 6 = 0

a = 1, b = 4, c = -6

Plugging all the values in the formula:

\rm x = \dfrac{-4 \pm\sqrt{4^2-4(1)(-6)}}{2(1)}

After calculating:

\rm x = \dfrac{-4 \pm\sqrt{40}}{2}

\rm x=-2+\sqrt{10},\ \ \ or \ \ \ x=-2-\sqrt{10}

Thus, the solution to the equation x(x+4) = 6 is x = -2 + √10 or x = -2 - √10 after solving with the quadratic formula.

Learn more about quadratic equations here:

brainly.com/question/2263981

#SPJ1

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bija089 [108]

Answer:

x = - \frac{1}{2}, x = \frac{3}{2}

Step-by-step explanation:

Given

x² - x - \frac{3}{4} = 0

Multiply through by 4 to clear the fraction

4x² - 4x - 3 = 0

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 4 × - 3 = - 12 and sum = - 4

The factors are + 2 and - 6

Use these factors to split the x- term

4x² + 2x - 6x - 3 = 0 ( factor the first/second and third/fourth terms )

2x(2x + 1) - 3(2x + 1) = 0 ← factor out (2x + 1) from each term

(2x + 1)(2x - 3) = 0

Equate each factor to zero and solve for x

2x + 1 = 0 ⇒ 2x = - 1 ⇒ x = - \frac{1}{2}

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = \frac{3}{2}

8 0
3 years ago
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Dovator [93]
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7 0
3 years ago
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B. Complete each inequality using &lt;or&gt; |-15| ○ |-5| -15 ○ -5​
ycow [4]

Answer:

|-15| > |-5|

-15 < -5​

Step-by-step explanation:

|-15| ○ |-5|

Absolute value means take the positive value

15 ○ 5

15 is greater than 5

15 > 5

-15 ○ -5​

negative 15 is less than -5

-15 < -5​

7 0
3 years ago
Simplify the expression so there is only one positive power for the base, -5. -5^7÷-5^2? A.1/5^9 B.-5^9 C.-5^5 D.1/5^5
stiks02 [169]

Answer:

-5^7/-5^2=5^7/5^2= 5^(7-2)=5^5 this is the answer

Step-by-step explanation:

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3 0
3 years ago
What is the simplified form of the following expression? 2√27+√12-3√3-2√12
LiRa [457]

Answer:

√3

Step-by-step explanation:

The given expression to be simplified is

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}

but

2 \sqrt{27}=2\sqrt{9 \times 3}=2 \times \sqrt{9}\times \sqrt{3}=2 \times 3 \times\sqrt{3}=6 \sqrt{3}

\sqrt{12}=\sqrt{4\times3}= \sqrt{4}\times \sqrt{3}=2\sqrt{3}

Since √12=2√3,this implies that,

2\sqrt{12}=2\times2\sqrt{3}=4 \sqrt{3}

Therefore,

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}=6\sqrt{3}+2\sqrt{3}-3 \sqrt{3} -4\sqrt{3}

=(6+2-3-4)\sqrt{3}

=\sqrt{3}

The simplified form of ,

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12} is √3

8 0
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