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valentina_108 [34]
2 years ago
14

If an isosceles triangle ABC has a vertex B, and AB=6×+3, BC BC=8x-1, and AC=10x-10, find x

Mathematics
1 answer:
saw5 [17]2 years ago
4 0

Using the given information, the value of x is 2

<h3>Calculating the length of the leg of an isosceles triangle</h3>

From the question, we are to determine the value of x

From the given information,

The isosceles triangle ABC has its vertex at B

If the vertex is at B, then we can conclude that

AB = BC (<em>Legs of an isosceles triangle are equal a</em>)

Also, from the given information,

AB = 6×+3

BC = 8x-1

Thus,

6x + 3 = 8x - 1

Collect like terms

3 + 1 = 8x - 6x

4 = 2x

2x = 4

∴ x = 4/2

x = 2

Hence, the value of x is 2

Learn more on Isosceles triangle here: brainly.com/question/18640272

#SPJ1

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Given the function f(c)=4|x-5|+3, for what values of x is f(x)=15?
Tju [1.3M]
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4 0
2 years ago
Write the equation for a parabola with a focus at (1,-4)(1,−4)left parenthesis, 1, comma, minus, 4, right parenthesis and a dire
lutik1710 [3]

Answer:

x = 3/2 - ((y + 4)²)/2

Step-by-step explanation:

The coordinates of the focus of the parabola = (1, -4)

The directrix of the parabola is the line, x = 2 (parallel to the y-axis)

The general form of a parabola having a directrix parallel to the y-axis is presented as follows;

(y - k)² = 4·p·(x - h)

The coordinates of the focus = (h + p, k)

The line representing the directrix is x = h - p

Therefore, by comparison, we have;

(1, -4) = (h + p, k)

k = -4

h + p = 1

∴ p = 1 - h

From the directrix, we have;

2 = h - p

∴ 2 = h - (1 - h) = 2·h - 1

2·h = 2 + 1

h = 3/2

p = 1 - h

∴ p = 1 - 3/2 = -1/2

p = -1/2

By substitution of the values of <em>k</em>, <em>p</em>, and <em>h</em>, in the general equation of the parabola, (y - k)² = 4·p·(x - h), we get;

(y - k)² = 4·p·(x - h) = (y - (-4))² = 4·(-1/2)·(x - (3/2)) = (y + 4)² = -2·(x - 3/2)

The equation of the parabola in vertex form is therefore;

x = (-1/2)·(y + 4)² + 3/2 = 3/2 - (y + 4)²/2

6 0
3 years ago
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