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Alla [95]
2 years ago
11

Write each polynomial in standard form. Then give the leading coefficient. You may need to combine like terms before writing the

polynomial in standard form.
18y^5-3y^8+10y

Mathematics
1 answer:
rewona [7]2 years ago
4 0

Answer: y(-3y^7+18y^4+10)

Step-by-step explanation:

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8 0
3 years ago
Distribute -x(7x+3).
Natasha_Volkova [10]

Answer:

-7x^2-3x

Step-by-step explanation:

-x * 7x + (-x) * 3

-7xx-3x

-7x^2-3x

5 0
3 years ago
X -2, -1, 0, 1, 2<br> y-<br><br> Complete the table for y=-3x+5
fomenos
Y- 11, 8, 5, 2, -1

Just replace the x in the equation, with the numbers of the x you already have.
5 0
4 years ago
the annual interest on 17,000 investment exceeds the interest on an 11,000 investment by 308 . the 17,000is invested at a 0.4% h
solmaris [256]

keeping in mind that

\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}

x =  percent rate for the 17000 investment.

y = percent rate for the 11000 investment.


so the amount for the 17000 interest will just be (x/100) * 17000, or namely 170x.

and the amount of interest earned for the 11000 is (y/100) * 11000, or just 110y.

now, regardless of what "x" and "y" are, we know that the interest from the 17000 is higher by 308 bucks, therefore 170x = 110y + 308.

we also know that the rate of <u>x</u> is higher as well than <u>y</u> by 0.4%, so then x = y + 0.4.


\bf \begin{cases} 170x=110y+308\\ \boxed{x}= y +0.4\\[-0.5em] \hrulefill\\ 170\left( \boxed{y+0.4} \right)=110y+308 \end{cases} \\\\\\ 170y+68=110y+308\implies 60y=240\implies y=\cfrac{240}{60}\implies \blacktriangleright y=\stackrel{\%}{4} \blacktriangleleft \\\\\\ x=y+0.4\implies \blacktriangleright x=\stackrel{\%}{4.4} \blacktriangleleft

3 0
4 years ago
I need help ASAP Which expression best represents the product of quantities m and n, increased by p?
nasty-shy [4]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

The correct option would be B. mn + p

'mn' means m multiplied by n

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8 0
3 years ago
Read 2 more answers
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