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sammy [17]
2 years ago
6

(b) Suppose you pick two marbles from the bag at random without replacement. Find the probability that both marbles are purple.

Mathematics
1 answer:
vichka [17]2 years ago
3 0

B) The probability that both marbles are purple is 2.22%.

C) The probability that you pick at least one purple marble is 98%.

<h3><u>Probability</u></h3>

The question is incomplete, since the number of marbles of each color in the bag is missing: 3 blue, 5 green, and 2 purple marbles.

Now, to answer the questions, the following calculations must be done:

  • B) 2/10 x 1/9 = X
  • 0.2 x 0.11111 = X
  • 0.022222 = X
  • X x 100 = 2.22

  • C) 100 - (2/9x9) = X
  • 100 - 2 = X
  • 98 = X

Learn more about probability in brainly.com/question/27656131

#SPJ1

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Answer:

The level is L = 0.084

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 0.08, \sigma = 0.01, n = 36, s = \frac{0.01}{\sqrt{36}} = 0.0017

What is the level L such that the probability that the average NOX level x for the fleet is greater than L is only 0.01?

This is X when Z has a pvalue of 1-0.01 = 0.99. So it is X when Z = 2.325.

Z = \frac{X - \mu}{\sigma}

By the Central limit theorem

Z = \frac{X - \mu}{s}

2.325 = \frac{X - 0.08}{0.0017}

X - 0.08 = 2.325*0.0017

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The level is L = 0.084

4 0
4 years ago
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