This is the concept of quadratic equations, solving the equation 2x^2-12x+20=0 using the formula we get:
x=[-b+/-sqrt(b^2-4ac)]/(2a)
from our equation, a=2,b=-12 and c=20
x=[-(-12+/-sqrt((-12)^2-4*2*20)]/(2*2)
x=[12+/-sqrt(144-160]/4
x=[12+/-sqrt(-16)]/4
x=[12+/-4i]/4
x=[3+\-i]
the answer is A] 3+/-i
Answer:
70°
Step-by-step explanation:
Since ∠BCA is supplementary with the 110° angle shown on the other side, ∠BCA = 180° (The measurement of a straight line) - 110° = 70°.
~Hope this helps!~
Answer:
He would be at the 15 yard line.
Step-by-step explanation:
The 40 yard gain would bring him to the 10 yard line (he caught it at the 50 yard line, so 50 - 40 = 10), but the 5 yards lost due to the tackle and push back would bring him to the 15 yard line (10 + 5 = 15).
Answer:
8%
Step-by-step explanation:
let,
this year population of students (pt)= 195
last year population of students (p)= 210
time(t)= 1 year
Population Change( R)= ?
we have,
pt= p( 1 - R/100)^t
195 = 210 ( 1 - R/100)^1
0.92= 1 - R/100
0.92-1= R/100
- 0.08 = - R/100
R= 0.08×100
R= 8%
Answer:
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Step-by-step explanation:
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