What is software engineering? What are the objectives of software engineering?

In the Application, "The Effect of FDI on Rentals and Wages in Singapore," the annual growth rate in real rental rates for the 1

stellarik [79]

Answer:

Explanation:

Production function: In simple words, production function refers to the functional relationship between the quantity of a good produced (output) and factors of production (inputs).

FDI: A foreign direct investment is an investment in the form of a controlling ownership in a business in one country by an entity based in another country.

Singapore has encouraged foreign firms to establish subsidiaries within its borders, especially in the electronics industry.
Singapore has the fourth-largest amount of FDI in the world.
What has happened to the rental rate and the wage?
Find in the attachment a table which shows much of this.

The annual growth rate in rental rates for the 1970-1990 period using the production function and marginal product was -5%.

6 0

3 years ago

Tiling is when a browser loads a background image and then repeats the image in both the vertical and horizontal directions unti

jeyben [28]

The correct answer is true

7 0

3 years ago

Read 2 more answers

A method to accept the number of drawers in the desk as input from the key board. This method returns the number of drawers to t

Julli [10]

Answer:

Following code takes the information about the wood from the user, do the process of calculating the value according to there type and numbers, then add the surcharge to it while giving the answer to the user.

For differentiating the type of woof i used the if then else statement while i used switch case statement for assigning the appropriate value according to the types of the wood will be processing in the program.

The code is given below:

Explanation:

Code:

namespace std;\\ any name instead of std.

{

class Program

{ \\ starting the main program

static void Main(string[ ] args)

{

int numberOfDrawers = 0;

string deskWoodType = "o";

double cost = 0;

drawersMeth(numberOfDrawers);

woodTypeMeth(deskWoodType);

CalculateCostMeth(numberOfDrawers, cost, deskWoodType);

OutPutCostMeth(deskWoodType , cost, numberOfDrawers);

}//end main

private static void drawersMeth(int numberOfDrawers)

{

int numOfDrawers;

Console.WriteLine("Enter the number of desk drawers");

numOfDrawers = Convert.ToInt16(Console.ReadLine());

numberOfDrawers = numOfDrawers;

}//end drawersMeth

private static string woodTypeMeth(string deskWoodType)

{

Console.WriteLine("Enter the desk wood type. (eg. type mahogany, oak, or pine)");

deskWoodType = Convert.ToString(Console.ReadLine());

switch (deskWoodType)

{

case "mahogany":

{

deskWoodType = "m";

break;

}

case "oak":

{

deskWoodType = "o";

break;

}

case "pine":

{

deskWoodType = "p";

break;

}

default:

{

deskWoodType = "error";

break;

}

return deskWoodType;

}// end woodTypeMeth

private static int CalculateCostMeth(string deskWoodType, int numberOfDrawers, int cost)

{

int pine = 100;

int oak = 140;

int other = 180;

int surchage = 30;

if (deskWoodType == "p")

cost = surchage + (numberOfDrawers *pine );

else if (deskWoodType == "o")

cost = surchage + (numberOfDrawers *oak );

else

cost = surchage + (numberOfDrawers *other );

return cost;

}// end CalculateCostMeth

private static void OutPutCostMeth(int numberOfDrawers, string deskWoodType, int cost)

{

double totalCost = cost;

Console.WriteLine("The number of drawers is {0}", numberOfDrawers);

Console.WriteLine("The wood finish you have selected is ", deskWoodType);

Console.WriteLine("The total cost is {0}", totalCost);

}//end outputCost

}//end class

}//end nameSpace

5 0

3 years ago

EASY POINTS

Dmitry [639]

Its answer D because I took the same test and it told me that my answer was right that I put down and it was D.

3 0

3 years ago

Building a String Library

maw [93]

Code:

def myAppend( str, ch ):
# Return a new string that is like str but with
# character ch added at the end
return str + ch

def myCount( str, ch ):
# Return the number of times character ch appears
# in str.

# initiaalizing count with 0
count = 0

# iterating over every characters present in str
for character in str:
# incrementing count by 1 if character == ch
if character == ch:
count += 1

# returning count
return count

def myExtend( str1, str2 ):
# Return a new string that contains the elements of
# str1 followed by the elements of str2, in the same
# order they appear in str2.

# concatenating both strings and returning its result
return str1 + str2

def myMin( str ):
# Return the character in str with the lowest ASCII code.

# If str is empty, print "Empty string: no min value"
# and return None.
if str == "":
print("Empty string: no min value")
return None

# storing first character from str in char
char = str[0]

# iterating over every characters present in str
for character in str:
# if current character is lower than char then
# assigning char with current character
if character < char:
char = character
# returning char
return char

def myInsert( str, i, ch ):
# Return a new string like str except that ch has been
# inserted at the ith position. I.e., the string is now
# one character longer than before.

# Print "Invalid index" if
# i is greater than the length of str and return None.

if i > len(str):
print("Invalid index")
return None

# str[:i] gives substring starting from 0 and upto ith position
# str[i:] gives substring starting from i and till last position
# returning the concatenated result of all three
return str[:i]+ch+str[i:]

def myPop( str, i ):
# Return two results:
# 1. a new string that is like str but with the ith
# element removed;
# 2. the value that was removed.
# Print "Invalid index" if i is greater than or
# equal to len(str), and return str unchanged and None
if i >= len(str):
print("Invalid index")
return str, None

# finding new string without ith character
new_str = str[:i] + str[i+1:]

# returning new_str and popped character
return new_str, str[i]

def myFind( str, ch ):
# Return the index of the first (leftmost) occurrence of
# ch in str, if any. Return -1 if ch does not occur in str.

# finding length of the string
length = len(str)

# iterating over every characters present in str
for i in range(length):
# returning position i at which character was found
if str[i]==ch:
return i
# returning -1 otherwise
return -1

def myRFind( str, ch ):
# Return the index of the last (rightmost) occurrence of
# ch in str, if any. Return -1 if ch does not occur in str.

# finding length of the string
length = len(str)

# iterating over every characters present in str from right side
for i in range(length-1, 0, -1):
# returning position i at which character was found
if str[i]==ch:
return i
# returning -1 otherwise
return -1

def myRemove( str, ch ):
# Return a new string with the first occurrence of ch
# removed. If there is none, return str.

# returning str if ch is not present in str
if ch not in str:
return str

# finding position of first occurence of ch in str
pos = 0

for char in str:
# stopping loop if both character matches
if char == ch:
break
# incrementing pos by 1
pos += 1

# returning strig excluding first occurence of ch
return str[:pos] + str[pos+1:]

def myRemoveAll( str, ch ):
# Return a new string with all occurrences of ch.
# removed. If there are none, return str.

# creating an empty string
string = ""

# iterating over each and every character of str
for char in str:
# if char is not matching with ch then adding it to string
if char!=ch:
string += char
# returning string
return string

def myReverse( str ):
# Return a new string like str but with the characters
# in the reverse order.

return str[::-1]

6 0

2 years ago