C) fair use
Hope this helps... mark as Brainliest plz
The answer is B , Hope this helps , I don’t speak Spanish but a little bit I understand , I’m sure that’s the correct answer answer
Answer:
#include <iostream>
using namespace std;
class Digits
{
public:
int num;
int read() //method to read num from user
{
cout<<"Enter number(>0)\n";
cin>>num;
return num;
}
int digit_count(int num) //method to count number of digits of num
{
int count=0;
while(num>0) //loop till num>0
{
num/=10;
count++; //counter which counts number of digits
}
return count;
}
int countDigits(int num) //method to return remainder
{
int c=digit_count(num); //calls method inside method
return num%c;
}
};
int main()
{
Digits d; //object of class Digits is created
int number=d.read(); //num is read from user
cout<<"\nRemainder is : "<<d.countDigits(number); //used to find remainder
return 0;
}
Output :
Enter number(>0)
343
Remainder is : 1
Explanation:
As program is missing to find errors , a logically write program is written to find the remainder when a number is divided by its number of digits. A class Digits is constructed which has public variable num and methods read(), digit_count(), countDigits().
- read() - This method reads value of num from the user and return num.
- digit_count() - This method takes a integer as parameter and counts the number of digits of a number passed as argument. while loop is used to increement the counter until num<0. This returns the value of count.
- countDigits() - This method takes a integer as a parameter and returns remainder when the argument is divided by number of digits of argument. Number of digits is calculated by using method digit_count().
At last in main method , object of Digits class is created and its methods are used to find the output.
In software: Logical Volume. In hardware it's usually called RAID (Redundant Array of Inexpensive Devices).
Answer:
Explanation:
Binary and hexadecimal values have the following pair equivalences.
We convert from binary to hexadecimal selecting groups of 4 binary from the binary code, from the least significant bits(at the right) to the most significant bits(at the left). The conversion is an hexadecimal "string" from the last group you converted to the first. So:
(a) %100011100101
So
(b) %1011001111
