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Jlenok [28]
2 years ago
6

Elizabeth lives in San Francisco and works in Mountain View. In the morning, she has 3 transportation options (take a bus, a cab

, or a train) to work, and in the evening she has the same 3 choices for her trip home.
If Elizabeth randomly chooses her ride in the morning and in the evening, what is the probability that she'll use a cab exactly one time?
(Both Percentage and Fraction if you can please)
Mathematics
2 answers:
mina [271]2 years ago
3 0

Answer:

If Elizabeth randomly chooses her ride in the morning and in the evening, 2/3 is the probability that she'll use a cab exactly one time

KATRIN_1 [288]2 years ago
3 0
Fraction=1/3
Percentage=100/3 which is 33.3%
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7/12 - □ = 1/6<br><br><br>□ = ________​
xz_007 [3.2K]
The answer is 5/12 because 1/6 converts to 2/6 and 7/12-2/6 is equal to 5/12
4 0
3 years ago
Solve the inequality and graph the solution g-3&gt;6
vaieri [72.5K]

Answer: It should be g > 9

Step-by-step explanation:

-Solve:

g-3>6

g-3+3>6+3

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So, Therefore, the result is g > 9

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3 years ago
Bill bought a shirt for $35.80 plus he paid an additional 7% in sales tax.
dezoksy [38]

Answer:

$2.50

Step-by-step explanation:

The cost for the shirt is 35.80

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35.80 x 0.07 = 2.50

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3 0
3 years ago
Find the following <br> (u•w)(2)=<br> (w•u)(2)=
Viefleur [7K]

Answer:

(u \circ w)(2) = -34

(w \circ u) = -49

Step-by-step explanation:

We are given these following functions:

u(x) = 4x + 2

w(x) = -5x + 1

The first step to solve this question is finding the composite functions. So

(u \circ w)(x) = u(w(x)) = u(-5x+1) = 4(-5x + 1) + 2 = -20x + 6

(w \circ u)(x) = w(u(x)) = w(4x + 2) = -5(4x+2) + 1 = -20x - 9

At x = 2

Now we replace x by 2 in each of the functions. So

(u \circ w)(2) = -20(2) + 6 = -40 + 6 = -34

(w \circ u)(2) = -20(2) - 9 = -40 - 9 = -49

5 0
3 years ago
In 1990, the mean duration of long-distance telephone calls originating in one town was 7.2 minutes. A long-distance telephone c
scoundrel [369]

Answer:

We know that In 1990, the mean duration of long-distance telephone calls originating in one town was 7.2 minutes. And we want to test if the mean duration of long-distance phone calls has changed from the 1990 mean of 7.2 minutes (alternative hypothesis) and the complement rule would represent the null hypothesis.

The correct system of hypothesis are:

Null hypothesis: \mu =7.2

Alternative hypothesis: \mu \neq 7.2

So then the best option for this case would be:

H0: μ = 7.2 minutes Ha: μ ≠ 7.2 minutes

Step-by-step explanation:

We know that In 1990, the mean duration of long-distance telephone calls originating in one town was 7.2 minutes. And we want to test if the mean duration of long-distance phone calls has changed from the 1990 mean of 7.2 minutes (alternative hypothesis) and the complement rule would represent the null hypothesis.

The correct system of hypothesis are:

Null hypothesis: \mu =7.2

Alternative hypothesis: \mu \neq 7.2

So then the best option for this case would be:

H0: μ = 7.2 minutes Ha: μ ≠ 7.2 minutes

And in order to test the hypothesis we can use a one sample t test or z test depending if we know the population deviation or not

4 0
3 years ago
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