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2 years ago

Graph a parabola whose vertex is at (3, 5) with y-intercept at y= 1

Mathematics

1 answer:

astraxan [27]2 years ago

4 0

Step-by-step explanation:

Substituting into vertex form, the equation is:

y = a(x-3)^2 + 5

The y-intercept is when x=0, so substituting this in,

1=a(0-3)^2 + 5

-4 = 9a

a=-4/9

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