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guajiro [1.7K]
2 years ago
10

Paint can be purchased in two sizes: 1 gallon for $45.99 or 1 quart for $14.99.(round to the hundredths place)a.unit ratio of 1

quart (32oz) for $14.99is __________b.unit ratio of 1 gallon (128oz) for $45.99is __________c.which is the better deal?
Mathematics
1 answer:
ExtremeBDS [4]2 years ago
3 0

Answer:

  a. $0.47 per ounce

  b. $0.36 per ounce

  c. the gallon size costs less per ounce

Step-by-step explanation:

A unit rate is a rate that is expressed with one unit in the denominator. That is, it is <some amount> per unit. The <some amount> value will generally depend on what unit is chosen. This problem suggests the desired unit is 1 oz of paint.

__

<h3>a.</h3>

Unit cost for a quart:

  ratio = cost/ounces = $14.99/(32 oz) ≈ $0.468/oz ≈ $0.47/oz

__

<h3>b.</h3>

Unit cost for a gallon:

  ratio = cost/ounces = $45.99/(120 oz) ≈ $0.359/oz ≈ $0.36/oz

__

<h3>c.</h3>

The cost per ounce is less for the gallon size. If at least 3 quarts of paint is needed, then buying it in the gallon size will cost less.

If less than 3 quarts are needed, then a gallon container will cost more than is necessary for the paint required. The "better deal" depends on the amount of paint required.

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Suzi can type around 50 words per minute she has less than a week to taper final research paper is the paper has to at least be
antiseptic1488 [7]

Answer:

2.5 hours

Step-by-step explanation:

(380/50) x 20

7.6 x 20

152

The final answer wold be 152 minutes or 2.5 hours

3 0
3 years ago
Mark borrowed $5,500 at 11.5 percent for five years. What is his monthly payment?
olya-2409 [2.1K]
Use the formula of the present value of an annuity ordinary which is
Pv=pmt [(1-(1+r/k)^(-kn))÷(r/k)]
Pv present value 5500
PMT monthly payment?
R interest rate 0.115
K compounded monthly 12
N time 5years
Solve the formula for PMT
PMT=Pv÷ [(1-(1+r/k)^(-kn))÷(r/k)]
PMT=5,500÷((1−(1+0.115÷12)^(
−12×5))÷(0.115÷12))
=120.95

So the answer is C

Hope it helps!
5 0
3 years ago
Read 2 more answers
Divid 15 into two parts such that the sum of their reciprocal is 3/10
emmasim [6.3K]
Let x and y be the 2 parts of 15 ==> x + y=15 (given)

Reciprocal of x and y ==> 1/x +1/y ==> 1/x + 1/y = 3/10 (given)


Let's solve  1/x + 1/y = 3/10 . Common denominator = 10.x.y (reduce to same denominator)

 ==> (10y+10x)/10xy = 3xy/10xy ==> 10x+10y =3xy

But x+y = 15 , then 10x+10y =150 ==> 150=3xy and xy = 50

Now we have the sum S of the 2 parts that is S = 15 and 
their Product = xy =50
Let's use the quadratic equation for S and P==> X² -SX +P =0
Or X² - 15X + 50=0, Solve for X & you will find:
The 1st part of 15 is 10 & the 2nd part is 5
4 0
3 years ago
If f(1) = 2 and f(n) = –2f(n − 1) then find the value of f(5).
dybincka [34]

Answer: 2f

Explanation:

f(1)=8

f(2)= 2(8) = 16

f(3) = 2(16) = 32

f(4) = 2(32) = 64

f(5) = 2(64) =128

6 0
2 years ago
Find the Range and Domain of the Binary relations
sukhopar [10]

Answer:

A = {3,5,6}

B = {1,3}

<u><em>A x B</em></u> = {(3,1),(3,3),(5,1),(5,3),(6,1),(6,3)}

Domain of A x B = (The x figures in ascending order)

=> {3,5,6}     (Figures repeating more than once must be written only 1 time)

Range of A x B = (The y figures in ascending order)

=> {1,3}

<u><em>B x A </em></u>= {(1,3),(3,3),(1,5),(3,5),(1,6),(3,6)}

Domain of B x A = {1,3}

Range of A x B = {3,5,6}

8 0
3 years ago
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