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Gennadij [26K]
3 years ago
7

The Hoffman family has bought one pizza on Friday night every week for the last 10 years. How many pizzas have they bought on Fr

iday nights? Enter your answer in the box.
Mathematics
1 answer:
prohojiy [21]3 years ago
7 0

Answer:

520 pizzas

Step-by-step explanation:

1 year = 52 weeks

Meaning the number of Fridays in a week = 52 Fridays

We are told that: The Hoffman family has bought one pizza on Friday night every week for the last 10 years.

Hence, the number of pizzas they bought in 1 year

= 52 Friday × 1 pizza

= 52 pizzas

For the last 10 years

= 52 pizzas × 10

= 520 pizzas

Hence, they have bought 520 pizzas in the last 10 years

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Based on the results from part C, which two statements correctly interpret actions the business should take? If material 2 is us
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The profit function is the difference between the cost and the revenue functions.

The true statement is (a) If material 2 is used, Carrie will earn a profit if she sells chairs for more than $150 each.

<h3>How to determine the true profit functions</h3>

From the complete questions, the profit functions are calculated as follows:

<u>Material 1</u>

P(x) = 5000000- 20000x - 200000x + 2000x^2

P(x) = 5000000-220000x + 2000x^2

<u>Material 2</u>

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<u>Material 3</u>

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Next, we test the options

Option 1: When material 2 is used

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Calculate P(151) using P(x) = 4000000-170000x+ 1000x^2

So, we have:

P(151) = 4000000-170000 * 151+ 1000* 151^2

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Option 2: When material 1 is used

A price is less than $50 is $49.

Calculate P(49) using P(x) = 5000000-220000x + 2000x^2

So, we have:

P(49) = 5000000-220000 * 49 + 2000* 49^2

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Option 3: When material 3 is used

Calculate P(45) and P(160) using P(x) = 2000000 -59000x - 270x^2

So, we have:

P(45) = 2000000 -59000 * 45 - 270 * 45^2

P(45) = -1201750

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So, we have:

P(30) = 4000000-170000*30+ 1000*30^2

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So, we have:

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P(40) = -600000

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