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Dvinal [7]
2 years ago
11

Using the digits 0 to 7 exactly once each, form a collection of positive integers whose sum is 100.

Mathematics
2 answers:
suter [353]2 years ago
7 0

Answer I found:

54+20+16+3+7

There are probably other answers

Yanka [14]2 years ago
4 0

63 + 17 + 20

36 + 54 + 10

you can get more

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Find the area of the figure below, formed from a triangle and a parallelogram.
IrinaK [193]

The area of the figure below is 96 mm².

<h3>Area </h3>

The area of a shape is the amount of space occupied by a two dimensional figure.

From the diagram

Area of the triangle = (1/2) * base * height = (1/2) * (8 + 8) * 6 = 48 mm²

Area of the parallelogram = base * height = 8 * 6 = 48 mm²

Area of figure = 48 + 48 = 96 mm²

The area of the figure below is 96 mm².

Find out more on Area at: brainly.com/question/25292087

8 0
3 years ago
2. Evaluate b^-3for b = 3.<br> •27<br> •1/9<br> •1/27<br> •-27
amm1812

Answer:

\underline{ \boxed{ \frac{1}{27} }}

Step-by-step explanation:

given \to \: b^{-3} \:  \\ if \:  b = 3. \to \\ 3^{-3}  =  \frac{1}{3 {}^{3} }  =  \underline{ \boxed{ \frac{1}{27} }}

♨Rage♨

8 0
3 years ago
Read 2 more answers
What is the equation of the line with an x-intercept of -1 and a y-intercept of 2? y = 2x - 2 y = - 2x 2 y = 2x 2
guajiro [1.7K]
X intercept = -1,  y = 0           (-1, 0)

<span>y intercept = 2,  x = 0           (0, 2)
</span>
slope between (-1, 0) and (0, 2):

slope = (2 -0)/(0 - -1) =  2/1 = 2,           m = 2

Using point   (-1, 0)   x₁ = -1, y₁ = 0

y - y₁ = m(x - x₁)

y - 0 = 2*(x - -1)

y = 2(x + 1)

y = 2x + 2
6 0
4 years ago
How many pairs of whole numbers that have a sum of 12
Ymorist [56]
<span>Total numbers of whole number that has a sum of 12. Let’s start counting
1. 11 + 1 = 12
2. 10 + 2 = 12
3. 9 + 3 = 12
4. 8 + 4 = 12
5. 7 + 5 = 12
6. 6 + 6 = 12
7. 12 + 0= 12

Therefore, there are 7 pairs of whole numbers being added that have a sum of 12.

</span>



6 0
3 years ago
Find the radius of the sphere with a volume of 32/81π cubic yards. Write your answer as a fraction in simplest form.
alexdok [17]

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ V=\frac{32\pi }{81} \end{cases}\implies \cfrac{32\pi }{81}=\cfrac{4\pi r^3}{3}\implies \cfrac{96\pi }{81}=4\pi r^3 \\\\\\ \cfrac{96\pi }{324\pi }=r^3\implies \cfrac{8}{27}=r^3\implies \sqrt[3]{\cfrac{8}{27}}=r\implies \cfrac{\sqrt[3]{8}}{\sqrt[3]{27}}=r\implies \cfrac{2}{3}=r

5 0
4 years ago
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