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1 year ago

Helppp quickkkkkkk enough points

Mathematics

2 answers:

xenn [34]1 year ago

8 0

Answer:

A or 57 7/9ft3

Step-by-step explanation:

13/3x10/3x4/1 = 520/9=57 7/9

Fynjy0 [20]1 year ago

7 0

Answer:

$a=2\\\\ b = 20\\\\ c = 47$

Step by step explanation:

$a(x) = 2(x+5)^2 -3\\\\~~~~~~~=2(x^2 +2 \cdot 5 \cdot x +5^2) -3\\\\~~~~~~~=2(x^2 +10x+25) -3\\\\~~~~~~~=2x^2 +20x +50 -3 \\\\~~~~~~~=2x^2 +20x +47\\\\\text{By comparing}~ 2x^2 +20x +47~ \text{with the standard form}~ ax^2 +bx+c,\\\\a=2,~ b = 20,~ c = 47$

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two bird populations were studied and formulas were developed for each populations growth. the populations p1 and p2 are given b

STatiana [176]

Answer:

$20 e^{k*10} = 60 e^{0.2*10}$

We can divide both sides by 20 and we got:

$e^{10k}= 3 e^{2}$

Now we can appply natural log on both sides and we got:

$10 k = ln(3e^2)$

Now we can divide both sides of the equation by 10 and we got:

$k = \frac{ln(3e^2)}{10}= 0.30986$

So then the aproximate value of k is 0.30986 and rounded would be 0.31

Step-by-step explanation:

We have the following two expression:

$p_1 = 20 e^{kt}$

$p_2 = 60 e^{0.2t}$

We know that the two populations were equal 10 years after the start of the study, so then we can create the following equation:

$20 e^{k*10} = 60 e^{0.2*10}$

We can divide both sides by 20 and we got:

$e^{10k}= 3 e^{2}$

Now we can appply natural log on both sides and we got:

$10 k = ln(3e^2)$

Now we can divide both sides of the equation by 10 and we got:

$k = \frac{ln(3e^2)}{10}= 0.30986$

So then the aproximate value of k is 0.30986 and rounded would be 0.31

6 0

3 years ago

Find the output, k, when the input, t, is –7.<br> k = 10t -19

kupik [55]

Answer:

k = - 89

Step-by-step explanation:

To calculate the output, substitute t = - 7 into the equation for output, that is

k = 10(- 7) - 19 = - 70 - 19 = - 89

7 0

3 years ago

Determine whether the series is convergent or divergent by expressing sn as a telescoping sum (as in Example 8). [infinity] 6 n2

vekshin1

Answer:

Step-by-step explanation:

given

$\sum\limits^\infty_{n=3}\frac{6}{n^2-1}=\sum\limits^\infty_{n=3}\frac{6}{(n-1)(n+1)}\\\\=\sum\limits^\infty_{n=3}\frac{6}{2}(\frac{1}{n-1}-\frac{1}{n+1})\\\\=\frac{6}{2}\sum\limits^\infty_{n=3}(\frac{1}{n-1}-\frac{1}{n+1})\\\\=3[(\frac{1}{2}-\frac{1}{4})+(\frac{1}{3}-\frac{1}{5})+(\frac{1}{4}-\frac{1}{6})+(\frac{1}{5}-\frac{1}{7})+...]\\\\=3[\frac{1}{2}+\frac{1}{3}]=3[\frac{3+2}{6}]=3[\frac{5}{6}]\\\\=\frac{15}{6}=\frac{5}{3}$

5 0

3 years ago

At a local swim club you can purchase an annual membership for 24 dollars which will allow you 1 dollar admission to the pool al

777dan777 [17]

Answer:

6 times

Step-by-step explanation:

Let the number of times you visit the pool = x

At a local swim club you can purchase an annual membership for 24 dollars which will allow you 1 dollar admission to the pool all summer.

= $24 + $1× x

= 24 + x

If you do not purchase the membership the pool admission is 5 dollars.

= 5 × x

= 5x

Hence:

24 + x = 5x

Collect like terms

24 = 5x - x

4x = 24

x = 24/4

x = 6 times

The number of times you must visit the pool with a membership that would equal the cost of paying full price is 6 times.

7 0

3 years ago

Can you copy worksheet

lys-0071 [83]

What worksheet or are you talking to somebody else

8 0

3 years ago