Answer:
12
Step-by-step explanation:
We can use the pythagorean theorem giving us:
a^2+b^2=c^2
(6sqr2)^2 + (6sqr2)^2 = c^2
72+72=c^2
144=c^2
12=c
Im sorry i need the point but I’ll calculated later once I’m done
We want to see how many solutions has an equation given some restrictions on the vectors of the equation.
We have 3 vectors in R2.
v₁, v₂, and v₃.
Where we know that v₁ and v₂ are parallel. And two vectors are parallel if one is a scalar times the other.
Then we can write:
v₂ = c*v₁
Where c is a real number.
Then our system:
x*v₁ + y*v₂ = v₃
Can be rewriten to:
x*v₁ + y*c*v₁ = v₃
(x + y*c)*v₁ = v₃
Assuming x, y, and c are real numbers, this only has a solution if v₁ is also parallel to v₃, because as you can see, the equation says that v₃ is a scallar times v₁.
Geometrically, this means that if we sum two parallel vectors, we will get a vector that is parallel to the two that we added.
If you want to learn more, you can read:
brainly.com/question/13322477
A calculator (addition) has one and exactly 1 output for every addition problem that you use as an imput
