We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
Answer:
i did it again i did i did not do did it
You would set it up like this: 150x + 280 = 255x The you just solve.
Answer:
Step-by-step explanation:
<em>The question has missing options ; However, the question is still solvable</em>
Given
Direction = 2 units left
Required
Shift the function by 2 units in the x axis
The general format of shifting a function along the x axis (by the left) is as follows
Where c represents the direction;
Since , then
