Answer:
The answer in slope-intercept form is y = -2/3 - 1
Step-by-step explanation:
The accumulated value of an investment if the money is a. compounded semiannually; b. compounded quarterly; c. compounded monthly; d. compounded continuously is $30731.4 $ , $30785.98 $30823.14 , 30841.95
<h3>What is Interest ?</h3>
Interest is the amount received by a person as a result of investing certain amount of money for a certain period of time.
It is given that
Principal = $ 25000
Time = 3 years
Interest Rate = 7 %
The amount is given by

Compounded semiannually
n = 2
Compounded Quarterly
n = 4
Compounded Monthly
n =12
Compounded Continuously
P = P₀ 
Therefore the accumulated value for
compounded Semiannually is

A = $30731.4
Compounded Quarterly

A = $30785.98
Compounded Monthly

A = $30823.14
Compounded Continuously

P = $30841.95
Therefore the accumulated value of an investment if the money is
a. compounded semiannually; b. compounded quarterly; c. compounded monthly; d. compounded continuously is
$30731.4 $ , $30785.98 $30823.14 , 30841.95
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Answer:
The size of Harry's loan is $9000.
Step-by-step explanation:
D(t) models Harry's remaining debt, in dollars, as a function of time t, in months that is given by :

We can see 200 is in negative that means it is getting deducted from the function. So, Harry must be paying this each month against his loan.
Lets put t = 0, that shows no payments have been made.
This will get the amount of loan, before any payments.

So,
Hence, the size of Harry's loan is $9000.
Answer:
x= -9/4=-2.25
Step-by-step explanation:
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