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2 years ago

Please help!! Consider the equation x/5 -2=11, where x represents the

Mathematics

1 answer:

ira [324]2 years ago

4 0

Answer:

x=65

Each NBA team can have a maximum of 15 players, 13 of which can be active each game.

65/5=13 so it's safe to say tgat 5 team can be crated

Step-by-step explanation:

x/5-2=11-->transposing x/5=11+2---->x=13×5--->x=65

verification 65/5-2=11--->13-2=11

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olya-2409 [2.1K]

Answer:

28.75 or 28 3/4

Step-by-step explanation:

This equation is made for Long Division:

115/4

4 cannot go into 1 evenly.

4 can go into 11, 2 times.

4x2=8

11-8=3

4 can go into 35, 8 times.

35-32=3

Add a zero at the end, then divide 4 into 30.

4 goes into 30, 7 times.

30-28=2

Add another zero, then divide again.

4 goes into 20, 5 times.

20-20=0

So, after you hit an even number you can stop dividing and put in your answer.

28.75

6 0

3 years ago

Peepeepoopooo I need help please

Irina18 [472]

Answer:

16.9

Step-by-step explanation:

We can use a proportion also in this case

51.6 : 23 = 38 : NO

NO = (38 x 23)/51.6 = 16.9

6 0

3 years ago

Y = x/3 - 4<br> Change this equation into y=mx+b form

dusya [7]

Y=3x+4 beacause the slope is m and b is the y-intercept

5 0

3 years ago

Read 2 more answers

Mr. Barresi is ordering pizzas for a team party. He knows that 7 pizzas will feed 25 students. If 300 students are attending the

liubo4ka [24]

Divide 300 by 25 and multiply with 7.

300/25 x 7 = X

7 0

3 years ago

Read 2 more answers

Suppose that 8% of the general population has a disease and that the test for the diesease is accurate 70% of the time. What is

balu736 [363]

Answer:

P = 0.332

Step-by-step explanation:

The probability of having the disease is 0.08

The probability that the test predicts with accuracy is 0.7.

We need to find the probability that the test positive for the disease.

Several cases may occur.

Case 1.

You have the disease and the test predicts it accurately

$P_1 = 0.08(0.7) = 0.056$

Case 2

You do not have the disease and the test predicts that you have it

$P_2 = 0.92(0.3) = 0.276$

Then the probability that the test predicts that you have the disease is the union of both probabilities P1 and P2

$P = P_1 + P_2\\\\P = 0.056 + 0.276\\\\P = 0.332$

8 0

3 years ago