Answer:
R(-3, 8)
Step-by-step explanation:
R = 2Q -P
R = 2(4, 3) -(11, -2) = (8-11, 6+2)
R = (-3, 8)
_____
You can derive the formula for the endpoint from the formula for the midpoint:
Q = (R + P)/2
R = 2Q - P . . . . . . multiply by 2 and subtract P
Answer:
D.
Step-by-step explanation:
Since this isn't a credit card, there are no interests or fees on a debit card, so A is incorrect. B is also incorrect. You only need identification when you are withdrawing or depositing at a bank, but purchases made in stores or online do not need your identification. You also don't need to record transactions in your checkbook (but it is recommend to keep track of purchases). Modern day technology already records transaction history and all you need to do is access it online.
D is correct because if someone steals your PIN for your debit card, they could go to stores and use that money. You can dispute charges and report to the bank if that happens.
Answer:
The 1st graph
Step-by-step explanation:
20 = 2t + 12
2t = 8
t = 4
At most she can afford 4 toppings which means she can have 4 toppings to less: t ≤ 4. This is represented in the 1st graph.
Answer:
2.547
Step-by-step explanation:
2pir=8
1.273=r
d=2r
2.547=d
<u>Answer:</u>
The length of a paper clip chain is directly proportional to the number of paper clips. If a chain with 65 paper clips has a length of 97.5 inches then the length of chain with 14 paper clips is 21 inches.
<u>Solution:</u>
Given that the length of a paper clip chain is directly proportional to the number of paper clips. Directly propotional means when the length of paper clip increases, then the number of paper clips also increases in same ratio.
Hence, by above definition, we get
------- eqn 1
From question, for a chain with 65 paper clips has a length of 97.5 inches, we get

Similarly, for a chain with 14 paper clips with length to be found, we get

Now by using eqn 1, we can calculate the length of 14 paper clips is,

Rearranging the terms we get,


Hence the length of chain with 14 paper clips is 21 inches.