Answer:
infinitely many answers, any odd integer n times π/2
ex. π/2, 3π/2, 5π/2
Step-by-step explanation:
we know that cos (π/2) or cos(3π/2) is 0
if one factor is 0, the product is zero, so we will not care about csc(x).
x is any odd integer n times π/2
Answer:
The third term is -25.
Step-by-step expanation:
d(1)=3
From this equation, we know the first term is 3.
d(n)=d(n−1)−14
This looks like a recursive formula. It is used to find the next term.
n is the variable for the term number that you are solving for.
d(n-1) is the term value before the what you are looking for.
To find the 2nd term, use the formula and substitute values known:
d(n)= d(n−1)−14
d(2) = d(2-1) - 14
d(2) = d(1) - 14
We know d(1)=3
d(2) = 3 - 14
d(2) = -11
Find the third term using the same method:
d(n) = d(n−1)−14
d(3) = d(3−1)−14
d(3) = d(2)−14
d(3) = -11 - 14
d(3) = -25
X=4
cross multiply
3x=12
x=4
<span>statements is not true
</span><span>D. -a = c
-a should be equal d, not c</span>
Answer:
16 hours
Step-by-step explanation:
let t be time, n the number of computers and w the number of workers, then
t = 
← k is the constant of variation
To find k use the condition n = 30, w = 6 and t = 10 , then
10 = 
( multiply both sides by 6 )
60 = 30k ( divide both sides by 30 )
2 = k
t = 
← equation of variation
When w = 5 and n = 40 , then
t = 
= 
= 16 hours
