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suter [353]
2 years ago
5

Why are elements classified?​

Chemistry
2 answers:
Yuki888 [10]2 years ago
8 0

elements are classified to study their properties and similarities and differences between each other more aqurately

hope it helps...!!!!

Oksi-84 [34.3K]2 years ago
6 0
Because it helps us to predict the properties of the elements and their compounds based on their positions in the Periodic Table.
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1) a solution with a hyrdrogen ion concentration of 1x10^-4 moles/liter would have a PH of what?
lana66690 [7]

Answer:

pH = -log(concentration of hydro.gen ion)

1. When con. of H ion is 1*10-4 mol/L

pH = -log(1*10-4) = -(-4) = 4

2. A solution with a pH of 1*10-12mol/L

pH = -log (1*10-12) = -(-12) = 12

The pH is 12 and the solution is basic or alkaline

3.A solution with a pH of 6 has the concentration of

pH = -log (H+)

(H+) = arc log -pH

(H+) = 1*10-6

Explanation:

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3 years ago
The genetic material of all organisms;made up of two twisted strands in a double helix
viva [34]
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7 0
3 years ago
Read carefully and choose the correct answer.ill mark brainliest​
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Answer:

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5 0
3 years ago
A sample of a compound contains 60.0 g C and 5.05 g H. Its molar mass is 78.12 g/mol. What is the compound’s molecular formula
ki77a [65]
The standard atomic weight of a C is 12, and the standard atomic weight of a H is 1.  So to find molar ratio of C and H in the compound: 60.0/12=5, 5.05/1=5. This means the molar ratio of C and H is 5:5, thus 1:1.  Assuming the molecular formula is CnHn, to find molar mass: 12n + 1n = 78.12.  n=78.12/(12+1) = 6.  So the compound's molecular formula is C6H6, benzene.
4 0
3 years ago
Read 2 more answers
How many grams of \text{NaCl}NaClstart text, N, a, C, l, end text will be produced from 18.0 \text{ g}18.0 g18, point, 0, start
Nezavi [6.7K]

Answer:

18.7887 g of NaCl

Explanation:

<em>The question reads - How many grams of NaCl will be produced from 18.0 g of Na and 23.0 g of Cl2?</em>

Let us start by writing out the balanced equation of the reaction:

Na + Cl2 ---> NaCl2

1 mole, each of Na and Cl2 is required to produce 1 mole of NaCl.

mole = mass/molar mass

Therefore

18 g of Na = 18/23 = 0.7826 mole

23 g of Cl2 = 23/71 = 0.3239 mole

In this case, the Na is in excess and the Cl2 becomes the limiting reagent. Hence

0.3239 mole of Cl2 will react with 0.3239 mole of Na to yield 0.3239 mole of NaCl.

mass of 0.3239 mole NaCl = 0.3239 x 58 = 18.7887 g

<u>Hence, 18.7887  grams of NaCl will be produced from 18.0 g of Na and 23.0 g of Cl2.</u>

3 0
3 years ago
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