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Naya [18.7K]
2 years ago
8

Several bird species feed in a certain species of tree. each bird species feeds in a different part of the tree. which factor ar

e the species of birds responding to in the environment?
a.) symbiosis
b.) competition
c.) parasitism
d.) omnivores
Biology
1 answer:
gavmur [86]2 years ago
4 0

Competition factor are the species of birds responding to in the environment. Thus, the correct option is B.

<h3>What is competition?</h3>

If numerous bird species eat on the same tree species, there will be fierce competition for food. As a result of the competition, each species will seek out a certain portion of the plant to feed on, most likely the part of the plant where it will be easiest to outcompete the competitors for food.

As a result, we may deduce that the right response is "They have evolved to diverse niches as a result of competition."

For more information regarding competition, visit:

brainly.com/question/15525466

#SPJ1

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Can an enzyme be recycled? Explain.
ser-zykov [4K]

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Cystic fibrosis is most common in individuals of Northern European descent, affecting 1 in 3200 newborns. Assuming that these al
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Answer:

0.0177

Explanation:

Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:

1/3200 = q² (have two CFTR mutant alleles) >>  

q = √ (1/3200) = 1/56.57 >>

- Frequency of the CFTR allele q = 1/56.57 = 0.0177  

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