Answer:
Heterozygous in class data:
⇒ .44
Heterozygous in North America:
⇒ .48
Explanation:
edge 2021
Answer:
the diagram explains the process of DNA digestion and DNA ligation, which is usually used in molecular cloning techniques
Explanation:
Molecular cloning can be defined as the process used to synthesize multiple copies of a particular DNA fragment. Molecular cloning requires the insertion of a foreign DNA fragment into an appropriate vector (e.g., a plasmid) through the action of specific enzymes that serve to cut and ligate DNA fragments. DNA digestion and DNA ligation use specific restriction enzymes and DNA ligases, respectively, in order to insert the foreign DNA fragment. For this purpose, restriction enzymes that generate single-stranded overhangs are preferred to create sticky ends which bind by complementary base pairing. Subsequently, a DNA ligase enzyme joins the DNA fragments together in order to create recombinant DNA molecules. DNA Ligation is often achieved by using a specific T4 DNA ligase, while there are many restriction enzymes that generate sticky-ends (e.g., BamHI, EcoRI, BaI228I, etc).
Wave height that should be it;)
Answer:
Carrying capacity for the jellyfish would reduce
Explanation:
Carrying capacity of a biological population in an ecosystem is the maximum number of population size the environment or habitat can conveniently cater for given the available resources such as, food, water supply, space etc.
The survival of the jelly fish largely in the small body of water would be largely dependent on how much food that is available.
The large number of mollusks harvested would reduce the available food in the small body of water, hence, reducing the carrying capacity for jellyfish.
Answer:
Yellow smooth - 9
Yellow wrinkle - 3
Green smooth- 3
Green Wrinkle - 1
Explanation:
Let the green color of the seed be depicted by "G" and the yellow color of the seed be depicted by "g"
Let the smooth the seed be depicted by "R" and wrinkled seed be depicted by "r"
F1 cross -
true breeding smooth green plant ( RRGG) and true breeding wrinkled yellow (rrgg)
F1 gamete will be RG, RG, rg, rg
F1 offspring will be RrGg , Thus all F1 offspring will be heterozygous smooth and yellow.
Thus, R is dominant over r and g is dominant over G
F2 Generation –
RrGg x RrGg
Gametes will be RG, Rg, rG, rg
RG Rg rG rg
RG RRGG RRGg RrGG RrGg
Rg RRGg RRgg RrGg Rrgg
rG RrGG RrGg rrGG rrGg
rg RrGg Rrgg rrGg rrgg
R is dominant over r and g is dominant over G
Genotypes are –
RRGG - 1 (Smooth Green)
RRGg-2 (Smooth yellow)
RrGG-2 (Smooth Green)
RrGg-4 (Smooth yellow)
RRgg- 1 (smooth yellow)
Rrgg – 2 (Smooth yellow)
rrGG – 1 (wrinkled Green)
rrGg – 2 (Wrinkled yellow)
rrgg – 1 (wrinkled yellow)
Yellow smooth - 9
Yellow wrinkle - 3
Green smooth- 3
Green Wrinkle - 1