A. (-4,12) B. (-6,6) C. (4,6) D. (13,10) E. (4,16)

Mathematics

1 answer:

Aleksandr-060686 [28]2 years ago

6 0

point that lies on the circle is, option C - (4,6)

hope it helps...!!!!

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The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is regi

Digiron [165]

Answer:

Yes. We can conclude that the percentage of the employed workers (p1), who have registered to vote, exceeds the percentage of unemployed workers (p2), who have registered to vote.

Step-by-step explanation:

Number of employed persons in the sample = 700

Number of unemployed person in the sample = 300

Number of employed persons who have registered to vote (p1) = 500

Number of unemployed persons who have registered to vote (p2) = 200

Proportion of registered voters who are employed = 500/700 = 71.4%

Proportion of registered voters who are unemployed = 200/700 = 28.6%

This implies that the percentage of registered voters who are employed is more than the percentage of registered voters who are employed. 71.4% (500/700) of the employed registered to vote as against 66.7% (200/300) of the unemployed who registered to vote.

We can conclude that of the 700 registered voters in the sample, 71.4% (500/700) are employed while 28.6% (200/700) are unemployed.

Therefore, the percentage of the employed workers (p1), who have registered to vote, exceeds the percentage of unemployed workers (p2), who have registered to vote.

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3 years ago

Solve the equation 2^(2x+1)+8=17×2^x.

myrzilka [38]

Oooh, looks fun

ok
erm
we might want to know some properties
$(x^m)(x^n)=x^{m+n}$
$(a^b)^c=a^{bc}$
if $a^m=a^n$ where a=a, then assume m=n

$2^{2x+1}=(2^{2x})(2^1)$
so
$(2^{2x})(2)+8=17(2^x)$
$(2^{2x})(2)+2^3=17(2^x)$
$(2^x)^2(2)+2^3=17(2^x)$
minus 17*2^x both sides
$(2^x)^2(2)+2^3-17(2^x)=0$
use u subsitution, u=2ˣ
$(u)^2(2)+2^3-17(u)=0$
solve $2u^2+8-17u=0$
or
$2u^2-17u+8=0$
ac method
2 times 8=16
what 2 number multiply to get -17 and add to get 16
-16 and -1
2u²-1u-16u+8=0
(2u²-1u)+(-16u+8)=0
u(2u-1)+(-8)(2u-1)=0
(u-8)(2u-1)+0
u-8=0
u=8

2u-1=0
2u=1
u=1/2

now
u=2ˣ

8=2ˣ
$2^3=2^x$
3=x

and
$\frac{1}{2}=2^x$
$2^{-1}=2^x$
-1=x

x=-1 and 3
neat problem

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Answer:

25+30+19= 74

74/130

Step-by-step explanation:

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