28x+-21 you simplify them first
Answer:
hi im going to work on this i wiil comment answer in a minute
Step-by-step explanation:
If a,b,c are the 3 positive integers
1/a +1/b +1/c > 6/abc
(bc+ac+ab)/abc >6/abc so
(bc+ac+ab)>6
The lowest positive integers that are different are 1,2,3 so the lowest value that (bc+ac+ab) could have is 1•2+2•3+1•3=2+6+3= 11 therefore
1/a +1/b +1/c > 6/abc is true
Looks fishy to me, the way this problem combines <, = and > symbols.
But anyway. Subtract 3x from both sides. You'll get
5 < x = 2 > 0 2 > 0 is true, but that's a different type of math problem (true or false). If you decide to substitute '1' for 2 > 0, then the "1" says "TRUE."
Then 5 < x = true, so you must find x values that are larger than 5.
That would be (5, infinity)
Please go back and ensure that you have copied down the original problem exactly as it appears.
Answer:
hola, por que? si 8xup3 euqlieas tja gnaot nighar
Step-by-step explanation: