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Feliz [49]
3 years ago
13

A line segment has the endpoints P(4, 7) and Q(6, 7). Find the coordinates of its midpoint M.

Mathematics
1 answer:
tatuchka [14]3 years ago
4 0

Answer:

(5, 7)

Step-by-step explanation:

M = (x1 + x2/2 , y1 + y2/2)

M = ( 4 + 6 /2 , 7 + 7 / 2)

M = 5, 7

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Mhanifa please help with this I find it super difficult! Thanks! I will mark brainliest! Random answers will be reported !
Artyom0805 [142]

Answer:

a)

The point that is equidistant to all sides of a triangle is called the <u>incenter</u>.

The incenter is located at the intersection of bisectors of the interior angles of a triangle.

b)

The point that is equidistant to all vertices of a triangle is called the <u>circumcenter</u>.  

The circumcenter is located at the intersection of perpendicular bisectors of the sides of a triangle.

c)

<em>See the attachment</em>

The blue lines and their intersection shows the incenter.

The red lines and their intersection shows the circumcenter.

As we see the red point- the <u>circumcenter </u>is closer to vertex B.

4 0
3 years ago
Select all the options that have the same value as 3 1/2 % of 20.
elena55 [62]
There are only three answers to this question. Answer-A, D,E
8 0
3 years ago
Find the area of the composite area
QveST [7]
Area of rectangle = LxW = 13x7 = 91

Area of triangle = bxh/2 = 7x7/2= 24.5

Total area= 91+24.5= 115.5 in^2
8 0
3 years ago
2 Points
Gnesinka [82]
Answers are A, C, and D!
3 0
3 years ago
Francis works at Carlos Bakery and is making cookie trays. She has 48 chocolate chip cookies, 64 rainbow cookies, and 120 oatmea
amm1812

The number of cookies and trays are illustrations of greatest common factors.

  • The number of trays is 8
  • 6 chocolate chips, 8 rainbows and 15 oatmeal cookies would fit each tray

The given parameters are:

\mathbf{Chocolate\ chip=48}

\mathbf{Rainbow=64}

\mathbf{Oatmeal=120}

<u>(a) The number of trays</u>

To do this, we simply calculate the greatest common factor of 48, 64 and 120

Factorize the numbers, as follows:

\mathbf{48 = 2 \times 2 \times 2 \times 2 \times 3}

\mathbf{64 = 2 \times 2 \times 2 \times 2 \times 2 \times 2}

\mathbf{120 = 2 \times 2 \times 2 \times 3 \times 5}

So, the GCF is:

\mathbf{GCF= 2 \times 2 \times 2}

\mathbf{GCF= 8}

Hence, the number of tray is 8

<u>(b) The number of each type of cookie</u>

We have

\mathbf{Chocolate\ chip=48}

\mathbf{Rainbow=64}

\mathbf{Oatmeal=120}

Divide each cookie by the number of trays

So, we have:

\mathbf{Chocolate\ chip = \frac{48}{8} = 6}

\mathbf{Rainbow = \frac{64}{8} = 8}

\mathbf{Oatmeal = \frac{150}{8} = 15}

Hence, 6 chocolate chips, 8 rainbows and 15 oatmeal cookies would fit each tray

Read more about greatest common factors at:

brainly.com/question/11221202

4 0
2 years ago
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