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mel-nik [20]
2 years ago
6

The equation y + 6 = one-third (X minus 9) is written in point-slope form. What is the equation written in slope-intercept form?

y = one-third x minus 3 y = one-third x + 9 y = one-third x minus 9 y = one-third x + 3
Mathematics
1 answer:
stiks02 [169]2 years ago
4 0

The equation written in slope-intercept form is y = (1/3)x -9

<h3>What is a linear Equation ?</h3>

A linear equation is that which can be represented in the form of y =mx +c , m is the slope and c is the intercept.

The given equation is

y+6 = 1/3(x-9)

To determine the slope and the intercept this equation needs to be solved

y+6 = (1/3)x - 3

y = (1/3)x -9

Therefore this is the slope intercept format , here

the slope = 1/3

intercept = -9

To know more about Linear Equation

brainly.com/question/11897796

#SPJ1

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5x + 2 -x = -4x

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2 = -4x -4x

2 = -8x

x = - 1/4


hope this helps
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Which graph represents the function h(x) = -(x + 6)3 - 3?
katrin2010 [14]

Answer:

-8

Step-by-step explanation:

3 0
3 years ago
On a quiet day without many witnesses, a 4.5 ft victim was shot by a sniper that was in a tower 780 ft away. If the angle of ele
azamat

Answer:

68.17m

Step-by-step explanation:

Please see attached a rough sketch of the scenario

Step one:

Given data

Height of victim= 4.5ft

The horizontal distance of the snipper from the building = 780ft

The angle of elevation= 5 degrees

Required

The vertical distance

The opposite= the vertical distance

789 ft = the adjacent

Step two:

Applying SOH CAH TOA

tan ∅= opp/adj

tan 5= opp/780

cross multiply we have

0.0874= opp/780

cross multiply we have

0.0874*780= opp

opp= 68.17m

The sniper shoots from a vertical distance of  68.17m

8 0
3 years ago
1 + 4 = 5<br> 2 + 5 = 12<br> 3 + 6 = 21<br> 5 + 8 = ?
Karolina [17]
45


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6 0
3 years ago
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Consider Functions F and G
Zanzabum

Answer:

A

Step-by-step explanation:

We are given two functions:

\displaystyle f(x)=\frac{x-16}{x^2+6x-40}\text{ and } g(x)=\frac{1}{x+10}

And we want to find:

f(x)+g(x)

Thus:

\displaystyle =\frac{x-16}{x^2+6x-40}+\frac{1}{x+10}

We can factor the denominator of the first term:

\displaystyle =\frac{x-16}{(x+10)(x-4)}+\frac{1}{x+10}

In order to add the two terms, we must have a common denominator. To achieve this, we can multiply to second term by (x - 4). Therefore:

\displaystyle =\frac{x-16}{(x+10)(x-4)}+\frac{1}{x+10}\Big(\frac{x-4}{x-4}\Big)

Multiply:

\displaystyle =\frac{x-16}{(x+10)(x-4)}+\frac{x-4}{(x+10)(x-4)}

Combine:

\displaystyle =\frac{(x-16)+(x-4)}{(x+10)(x-4)}

Simplify:

\displaystyle =\frac{2x-20}{(x+10)(x-4)}

We can expand the denominator:

\displaystyle =\frac{2x-20}{x^2+6x-40}

Therefore, our answer is A.

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3 years ago
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