Answer: x=7
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
2(6x+5)=94
(2)(6x)+(2)(5)=94(Distribute)
12x+10=94
Step 2: Subtract 10 from both sides.
12x+10−10=94−10
12x=84
Step 3: Divide both sides by 12.
12x
12
=
84
12
x=7
Choice A is the answer which is the point (1,-1)
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How I got this answer:
Plug each point into the inequality. If you get a true statement after simplifying, then that point is in the solution set and therefore a solution. Otherwise, it's not a solution.
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checking choice A
plug in (x,y) = (1,-1)



This is true because -3 is equal to itself. So this is the answer.
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checking choice B
plug in (x,y) = (2,4)



This is false because 0 is not to the left of -3, nor is 0 equal to -3. We can cross this off the list.
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checking choice C
plug in (x,y) = (-2,3)



This is false because 7 is not to the left of -3, nor is 7 equal to -3. We can cross this off the list.
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checking choice D
plug in (x,y) = (3,4)



This is false because -2 is not to the left of -3, nor is -2 equal to -3. We can cross this off the list.
Answers:
Angle A = 104 degrees
Angle B = 76 degrees
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Supplementary angles add to 180 degrees.
A+B = 180
(3x-7)+(2x+2) = 180
5x-5 = 180
5x-5+5 = 180+5 ... add 5 to both sides
5x = 185
5x/5 = 185/5 .... divide both sides by 5
x = 37
Use x =37 to find
Angle A = 3x-7 = 3*37-7 = 111-7 = 104 degrees
Angle B = 2x+2 = 2*37+2 = 74+2 = 76 degrees
As a check: A+B = 104+76 = 180 so that helps confirm the answer
Answer:
34.6 units
Step-by-step explanation:
The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.
The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).
Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:
Distance between point A(-6, 2) and point B(2, 6):

Let,





(nearest tenth)
Distance between B(2, 6) and C(7, 1):

Let,





(nearest tenth)
Distance between C(7, 1) and D(3, -5):

Let,





(nearest tenth)
Distance between D(3, -5) and A(-6, 2):

Let,





(nearest tenth)
Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units
The equation is 30x + 25
since the x is with the 30, that would be the cost per lesson, because you would multiply 30 by the number of lessons(x)