Given:
Consider the equation is:
To prove:
by using the properties of logarithms.
Solution:
We have,
Taking left hand side (LHS), we get
![\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_ab%3D%5Cdfrac%7B%5Clog_x%20a%7D%7B%5Clog_x%20b%7D%5Cright%5D)
![[\because \log x^n=n\log x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog%20x%5En%3Dn%5Clog%20x%5D)
Hence proved.
Two vertical angles are formed. These angles are also equal to each other.
Answer:
Step-by-step explanation:
let the side of outer square=2x
then x²+x²=(20√2)²
2x²=800
x²=400
x=√400=20 in
2x=2×20=40 in
area of outer square=40²=1600 in²
area of inner square=(20√2)²=800 in²
area of shaded region A=1600-800=800 in²
Answer: k = 12
<u>Step-by-step explanation:</u>
x² + kx + 36 = 0
In order for x to have exactly one solution, it must be a perfect square.
(x + √36)² = 0
(x + 6)² = 0
(x + 6)(x + 6) = 0
x² + 6x + 6x + 36 = 0
x² + 12x + 36 = 0
k = 12
Answer:
12
Step-by-step explanation:
