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tamaranim1 [39]
2 years ago
15

Help me deadline today

Mathematics
1 answer:
weeeeeb [17]2 years ago
8 0

Answer:

6

Step-by-step explanation:

The equation becomes 9 *4 * 1/6. Then you simplify and get 6.

Please mark me as Brainliest if it is correct, thx.

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1.05+2.24= x-3.12 ????????//
coldgirl [10]

1.05+2.24= x-3.12

add the left side

3.29 = x -3.12

add 3.12 to each side

3.29 +3.12 = x

6.41 =x

5 0
3 years ago
Steve invests in a circus production. The cost includes an overhead of $84,000, plus production costs of $2000 per performance.
Dima020 [189]

Answer:

14

Step-by-step explanation:

Given that Steve  invests in a circus production. The cost includes an overhead of $84,000, plus production costs of $2000 per performance. A sold-out performance brings in $8000.

Sales per performance =8000

Production cost per performance =2000

Contribution per performance = 8000-2000=6000

Overhead costs = 84000

Break even units = overhead cost/contribution per performance

= \frac{84000}{6000} \\=14

14 performances should be done to break even

3 0
3 years ago
Plz help and I will give brainliest
DiKsa [7]

Answer:

a. f<g is one of them. On the number line, g is closest to 0, meaning it is greater than f.

b. h>0 is one answer. H is to the right of 0, meaning that h is greater than 0.

c. im sorry, i dont know.

Step-by-step explanation:

If this is graded, I hope you get a good grade!

4 0
3 years ago
A cola-dispensing machine is set to dispense 8 ounces of cola per cup, with a standard deviation of 1.0 ounce. The manufacturer
pshichka [43]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: ounces per cup dispensed by the cola-dispensing machine.

The population mean is known to be μ= 8 ounces and its standard deviation σ= 1.0 ounce. Assuming the variable has a normal distribution.

A sample of 34 cups was taken:

a. You need to calculate the Z-values corresponding to the top 5% of the distribution and the lower 5% of it. This means you have to look for both Z-values that separates two tails of 5% each from the body of the distribution:

The lower value will be:

Z_{o.o5}= -1.648

You reverse the standardization using the formula Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~N(0;1)

-1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 7.72ounces

The lower control point will be 7.72 ounces.

The upper value will be:

Z_{0.95}= 1.648

1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 8.28ounces

The upper control point will be 8.82 ounces.

b. Now μ= 7.6, considering the control limits of a.

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-7.6)/(1/√34))- P(Z≤7.72-7.6)/(1/√34))

P(Z≤7.11)- P(Z≤0.70)= 1 - 0.758= 0.242

There is a 0.242 probability of the sample means being between the control limits, this means that they will be outside the limits with a probability of 1 - 0.242= 0.758, meaning that the probability of the change of population mean being detected is 0.758.

b. For this item μ= 8.7, the control limits do not change:

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-8.7)/(1/√34))- P(Z≤7.72-8.7)/(1/√34))

P(Z≤-2.45)- P(Z≤-5.71)=0.007 - 0= 0.007

There is a 0.007 probability of not detecting the mean change, which means that you can detect it with a probability of 0.993.

I hope it helps!

5 0
2 years ago
Read 2 more answers
LM and N O are parallel lines what therom can we prove by translating the plane along the directed line segment M N?
Nezavi [6.7K]

Answer:

no idea lol

Step-by-step explanation:

6 0
2 years ago
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