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tamaranim1 [39]
1 year ago
15

Help me deadline today

Mathematics
1 answer:
weeeeeb [17]1 year ago
8 0

Answer:

6

Step-by-step explanation:

The equation becomes 9 *4 * 1/6. Then you simplify and get 6.

Please mark me as Brainliest if it is correct, thx.

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Find the distance between points P(9,8) and Q(7,6) to the nearest tenth.
sergey [27]

Answer:

2.8 units

Step-by-step explanation:

Think of this distance as the hypotenuse of a right triangle that has a vertical leg and a horizontal one as well.

Going from P to Q, the change in x is 2 and the change in y is also 2.

Thus, by the Pythagorean Theorem, this desired distance is:

d = √(2^2 + 2^2) = 2√2 units, or 2.8 units

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2 years ago
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Liono4ka [1.6K]

Answer:

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Step-by-step explanation:

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3 years ago
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Ostrovityanka [42]
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3 years ago
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a minivan can hold up to 7 people. How many minivans are needed to take 45 people to a basketball game?
DaniilM [7]
Answer=7 minivans

45/7=6.4

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lim x rightarrow 0 1 - cos ( x2 ) / 1 - cosx The limit has to be evaluated without using l'Hospital'sRule.
zaharov [31]

Answer with Step-by-step explanation:

Given

f(x)=\frac{1-cos(2x)}{1-cos(x)}\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-(cos^2{x}-sin^2{x})}{1-cos(x)})\\\\(\because cos(2x)=cos^2x-sin^2x)\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-cos^2x}{1-cos(x)}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}(\frac{(1-cosx)(1+cosx)}{1-cosx}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}((1+cosx)+\frac{sin^2x}{1-cosx})\\\\\therefore \lim_{x \rightarrow 0}f(x)=1

6 0
2 years ago
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