Caitlin has finished her schooling and training to be a dental hygienist. She has two job offers that she is considering.

The latest online craze is a new game, Khan on Seven. You get

Alika [10]

Do you have any answer choices?

8 0

3 years ago

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Will mark brainliest if amswer right pitcure included

just olya [345]

Answer:

QPT is obtuse

SPQ is acute

TPR is right

Step-by-step explanation:

Took geometry two years ago

8 0

3 years ago

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To solve a system of inequalities so you can graph it how do you change these two equations into something like the two that are

Zigmanuir [339]

Explanation

Problem #2

We must find the solution to the following system of inequalities:

$\begin{gathered} 3x-2y\leq4, \\ x+3y\leq6. \end{gathered}$

(1) We solve for y the first inequality:

$-2y\leq4-3x.$

Now, we multiply both sides of the inequality by (-1), this changes the signs on both sides and inverts the inequality symbol:

$\begin{gathered} 2y\ge-4+3x, \\ y\ge\frac{3}{2}x-2. \end{gathered}$

The solution to this inequality is the set of all the points (x, y) over the line:

$y=\frac{3}{2}x-2.$

This line has:

• slope m = 3/2,

,

• y-intercept b = -2.

(2) We solve for y the second inequality:

$\begin{gathered} x+3y\leq6, \\ 3y\leq6-x, \\ y\leq-\frac{1}{3}x+2. \end{gathered}$

The solution to this inequality is the set of all the points (x, y) below the line:

$y=-\frac{1}{3}x+2.$

This line has:

• slope m = -1/3,

,

• y-intercept b = 2.

(3) Plotting the lines of points (1) and (2), and painting the region:

• over the line from point (1),

,

• and below the line from point (2),

we get the following graph:

Answer

The points that satisfy both inequalities are given by the intersection of the blue and red regions:

8 0

11 months ago

What is the square root of 1/121

icang [17]

Answer:

11

Step-by-step explanation:

example 11×11 = 121

therefore squreroots = 11

8 0

2 years ago

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Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf

kobusy [5.1K]

Answer:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We have the following data given:

$\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by $\alpha=1-0.93=0.07$ and $\alpha/2 =0.035$ . And the critical value would be given by:

$z_{\alpha/2}=-1.811, z_{1-\alpha/2}=1.811$

The confidence interval is given by:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

4 0

3 years ago