Answer:
The probability of the heads up on the first three flips and not on the last two flips will be 1/32.
Step-by-step explanation:
As, the probability of head up when one time coin is flipped is 1/2. And it is said in the question that you must get heads in the first three flips.
So, for the first three flips the probability is = (1/2)^3 = 1/8
And for the last two flips you want to get not heads up.
Then, the probability is = (1/2)^2 = 1/4
Hence, your overall probability will be = 1/8 × 1/4 = 1/32 .
Answer:c is your answer
Step-by-step explanation:90+90+38=218 then 360-218= 142
The answer to 52\8 is 6.5.
In order to find the probability of both marbles being drawn being the same colour, the probability of each marble being drawn has to first be found and then multiply both probability to find the probability of two orange marble being drawn consecutively.
Now, the probability of drawing an orange marble = ⁴/₉
since a marble has been removed and wasn't replaced then there are now 5 pink + 3 orange marbles (8 marbles in total) in the bag.
∴ the probability of the second marble drawn being orange = ³/₈
⇒ the probability of <span>two orange marbles in a row without the first being replaced = </span>⁴/₉<span> </span>× ³/₈ = ¹/₆