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KatRina [158]
2 years ago
11

In ΔLMN, n = 510 cm, l = 820 cm and ∠M=20°. Find ∠L, to the nearest degree

Mathematics
1 answer:
Dafna11 [192]2 years ago
8 0

The angular measure L is : 47°

<h3>What are angles?</h3>

Angles are formed when two lines meet.

Analysis:

Firstly, we calculate for m using cosine rule.

m^{2} = 510^{2} + 820^{2} -2(510)(820) cos 20

m^{2} = 260100 + 672400 -83600(0.9396)

m^{2} = 146618.56

m = \sqrt{146618.56} = 382.9cm

using sine rule to find ∠L

382.9/sin20 = 820/sinL

sinL = 820sin20/382.9

sinL = 820(0.342)/382.9

sinL = 0.732

L = sin inverse of 0.732 = 47°

In conclusion, ∠L is 47°

Learn more about sine and cosine rule: brainly.com/question/4372174

#SPJ1

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\vec F_3=\langle x,y,z\rangle is a force vector such that

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there are 148 juniors and 272 seniors attending prom this year. if there must be three chaperones per 60 students, how many chap
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21 chaperones are needed for 420 students.

Step-by-step explanation:

No. of juniors = 148

No. of seniors = 272

Total = 148+272 = 420 students

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1 chaperone = \frac{60}{3}=20\ students

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Let,

x be the number of chaperons for 420 students.

Ration of chaperones to students = x:420

Using proportion

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Keywords: ratio, proportion

Learn more about ratios at:

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