Answer:
The system has infinitely many solutions
Step-by-step explanation:
Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.
An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.
There are three elementary matrix row operations:
- Switch any two rows
- Multiply a row by a nonzero constant
- Add one row to another
To solve the following system
Step 1: Transform the augmented matrix to the reduced row echelon form
![\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]](https://tex.z-dn.net/?f=%5Cleft%5B%20%5Cbegin%7Barray%7D%7Bcccc%7D%201%20%26%20-3%20%26%20-2%20%26%200%20%5C%5C%5C%5C%20-1%20%26%202%20%26%201%20%26%200%20%5C%5C%5C%5C%202%20%26%203%20%26%205%20%26%200%20%5Cend%7Barray%7D%20%5Cright%5D)
This matrix can be transformed by a sequence of elementary row operations
Row Operation 1: add 1 times the 1st row to the 2nd row
Row Operation 2: add -2 times the 1st row to the 3rd row
Row Operation 3: multiply the 2nd row by -1
Row Operation 4: add -9 times the 2nd row to the 3rd row
Row Operation 5: add 3 times the 2nd row to the 1st row
to the matrix
![\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]](https://tex.z-dn.net/?f=%5Cleft%5B%20%5Cbegin%7Barray%7D%7Bcccc%7D%201%20%26%200%20%26%201%20%26%200%20%5C%5C%5C%5C%200%20%26%201%20%26%201%20%26%200%20%5C%5C%5C%5C%200%20%26%200%20%26%200%20%26%200%20%5Cend%7Barray%7D%20%5Cright%5D)
The reduced row echelon form of the augmented matrix is
which corresponds to the system
The system has infinitely many solutions.
What ? Don't make since bro
The range of a relation is the possible output values, the y-values.
Complete question :
Cheddar Cheese
$3/lb
Swiss Cheese
$5/lb
Keisha is catering a luncheon. She has $30 to spend on a mixture of Cheddar cheese and Swiss cheese. How many pounds of cheese can Keisha get if she buys only Cheddar cheese? Only Swiss cheese? A mixture of both cheeses?
What linear equation in standard form can she use to model the situation?
Answer:
10 lbs of cheddar cheese
6 lbs of Swiss cheese
$3a + $5b = $30
Step-by-step explanation:
Given that :
Cheddar cheese = $3/lb
Swiss cheese = $5/lb
Total amount budgeted for cheese = $30
How many pounds of cheese can Keisha get if she buys only Cheddar cheese?
Pounds of cheedar cheese obtainable with $30
Total budget / cost per pound of cheddar cheese
$30 / 3 = 10 pounds of cheedar cheese
Only Swiss cheese?
Pounds of cheedar cheese obtainable with $30
Total budget / cost per pound of Swiss cheese
$30 / 5 = 6 pounds of Swiss cheese
A mixture of both cheeses?
What linear equation in standard form can she use to model the situation?
Let amount of cheddar cheese she can get = a
Let amount of Swiss cheese she can get = b
Hence,
(Cost per pound of cheddar cheese * number of pounds of cheddar) + (Cost per pound of Swiss cheese * number of pounds of Swiss cheese) = total budgeted amount
(3 * a) + (5 * b) = $30
$3a + $5b = $30
Let XXX and YYY be the following sets: X = \{9, 25\}X={9,25}X, equals, left brace, 9, comma, 25, right brace Y = \{1, 4, 9,16,25
Dmitry_Shevchenko [17]
Answer:
The answer is "
"
Step-by-step explanation:
Given value:
When we subtract set X - Y it means, that it will give only, that value which is not available on the set Y.
