Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
Answer:
57.8325
Step-by-step explanation:
74=128% x whole
74/128%= whole
57.8125=price if the present
Answer: 3
Explanation: (7x7) + (7x3) = 7x10
7x7 = 49
7x3 = 21
7x 10 = 70
49+21= 70
Hope this helps! <3
Answer:
250 students
Step-by-step explanation:
Another way of saying this is:
40% of all six-grade students are 100 of them.
So,
40% of total is equal to 100
We can translate this into an algebraic equation and solve for the total number of students.
Let total number of students be "t"
Also, note "of" means "multiplication" and "is" means "equal"
Lets translate word equation to algebraic:
<em>"40% of total is equal to 100"</em>
40% * t = 100
Converting percentage to decimal by dividing by 100, we have:
40% = 40/100 = 0.4
Now, we have:
0.4 * t = 100
We can now solve for t:
Hence,
the total number of students is 250
Answer:
1. y/4 = 15/20 or (y times 5)/20 = 15/20
Y = 3
Step-by-step explanation:
First, make sure the denominators are the same and then it will be up to multiplication and division.
