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3 years ago

Is this a function ???????

Mathematics

2 answers:

laila [671]3 years ago

7 0

No, a function has one input and one output

alisha [4.7K]3 years ago

6 0

No , because a function has one input and output

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I need help with the first one please someone help I don’t get it!

levacccp [35]

Answer:

2.2

Step-by-step explanation:

3 0

3 years ago

lesa saved 17,689 pennies lynn saved 1614 connie saved 176 pennies how many pennies did they save altogether

Goshia [24]

To find your answer you must add them all together :
17,689
1,614
+ 176
_________
19,479

5 0

4 years ago

Koto’s average velocity along her route was 4. 5 m/s. She started at her house and traveled 15,000 meters north, 5,000 meters ea

Lostsunrise [7]

The time taken for her trip is 3 hours.

<h3>Given that</h3>

Koto’s average velocity along her route was 4. 5 m/s.

She started at her house and traveled 15,000 meters north, 5,000 meters east, 20,000 meters south, and then 5,000 meters west.

<h3>We have to determine</h3>

What was the time of her trip?

<h3>According to the question</h3>

She started at her house and traveled 15,000 meters north, 5,000 meters east, 20,000 meters south, and then 5,000 meters west.

<h3 /><h3>The calculation of such a trip of Koto can be done by applying the known formula of Time when the Speed is multiplied by Distance to compute the actual time of the trip.</h3>

The formula to calculate the time for her trip is;

$\rm Speed = \dfrac{ Distance}{Time}\\
\\
Time = \dfrac{Distance}{Speed}\\
\\
$

Using the formula above, the commute in each direction is added as 45000 meters or 45 kilometers.

If Koto's average speed is 4.5 meters per second, then she travels roughly 270 meters in one minute.

Substitute all the values in the formula;

$\rm\ Time = \dfrac{Distance}{Speed}\\\\ Time = \dfrac{45000}{270}\\
\\
Time =166.7$

Converting minutes into hours,

$\rm Hours = \dfrac{Minute}{60}\\
\\
Hours = \dfrac{166.7}{60}\\
\\
Hours = 2.77 \\
\\
= 3\ hours$

Hence, the time taken for her trip is 3 hours.

To know more about Time and Distance click the link given below.

brainly.com/question/4433818

5 0

3 years ago

What is an equation of the line that passes through the points (-3,8) and (-7,8) help pleaseeee

Bingel [31]

Answer:

y = 8

Step-by-step explanation:

find slope first

(8-8)/(-7-(-3)) = 0/-4, the slope is 0

You know that 8 is y intercept

Equation: y = 0x + 8, or y = 8

3 0

3 years ago

Calculus 2 Master needed, evaluate the indefinite integral of: <img src="https://tex.z-dn.net/?f=%5Cint%5C%28%20%28lnx%29%5E2%7D

viva [34]

Answer:

$\int (\ln(x))^2dx=x(\ln(x)^2-2\ln(x)+2)+C$

Step-by-step explanation:

So we have the indefinite integral:

$\int (\ln(x))^2dx$

This is the same thing as:

$=\int 1\cdot (\ln(x))^2dx$

So, let's do integration by parts.

Let u be (ln(x))². And let dv be (1)dx. Therefore:

$u=(\ln(x))^2\\\text{Find du. Use the chain rule.}\\\frac{du}{dx}=2(\ln(x))\cdot\frac{1}{x}$

Simplify:

$du=\frac{2\ln(x)}{x}dx$

And:

$dv=(1)dx\\v=x$

Therefore:

$\int (\ln(x))^2dx=x\ln(x)^2-\int(x)(\frac{2\ln(x)}{x})dx$

The x cancel:

$=x\ln(x)^2-\int2\ln(x)dx$

Move the 2 to the front:

$=x\ln(x)^2-2\int\ln(x)dx$

(I'm not exactly sure how you got what you got. Perhaps you differentiated incorrectly?)

Now, let's use integrations by parts again for the integral. Similarly, let's put a 1 in front:

$=x\ln(x)^2-2\int 1\cdot\ln(x)dx$

Let u be ln(x) and let dv be (1)dx. Thus:

$u=\ln(x)\\du=\frac{1}{x}dx$

And:

$dv=(1)dx\\v=x$

So:

$=x\ln(x)^2-2(x\ln(x)-\int (x)\frac{1}{x}dx)$

Simplify the integral:

$=x\ln(x)^2-2(x\ln(x)-\int (1)dx)$

Evaluate:

$=x\ln(x)^2-2(x\ln(x)-x)$

Now, we just have to simplify :)

Distribute the -2:

$=x\ln(x)^2-2x\ln(x)+2x$

And if preferred, we can factor out a x:

$=x(\ln(x)^2-2\ln(x)+2)$

And, of course, don't forget about the constant of integration!

$=x(\ln(x)^2-2\ln(x)+2)+C$

And we are done :)

8 0

3 years ago