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kobusy [5.1K]
2 years ago
8

Which functions have a y-intercept that is greater than the y-intercept of the function g(x) = |x + 3| + 4? Check three

Mathematics
1 answer:
Marina CMI [18]2 years ago
7 0

Answer:

A

Step-by-step explanatio

If i were to give my judge on this <9M+13=5^9

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(X^3+1)dividend (x-1)
bazaltina [42]

x^3=x\cdot x^2 and x^2(x-1)=x^3-x^2. So we have a remainder of

(x^3+1)-(x^3-x^2)=x^2+1

x^2=x\cdot x and x(x-1)=x^2-x. Subtracting this from the previous remainder gives a new remainder

(x^2+1)-(x^2-x)=x+1

x=x\cdot1 and 1(x-1)=x-1. Subtracting this from the previous remainder gives a new one of

(x+1)-(x-1)=2

and we're done since 2 does not divide x. So we have

\dfrac{x^3+1}{x-1}=x^2+x+1+\dfrac2{x-1}

4 0
3 years ago
Please help I will mark Brainly
valina [46]

I believe the answer is A. X-Coordinate


7 0
3 years ago
Read 2 more answers
(6x + 7) - (9x + 9) simpilest form pls
My name is Ann [436]

Answer:

-3x+16

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Given the quadratic equation <img src="https://tex.z-dn.net/?f=y%20%3D%202%28x%20-1%29%5E%7B2%7D%20%2B%208" id="TexFormula1" tit
Sunny_sXe [5.5K]

Answer:

Part 1) "a" value is 2

Part 2) The vertex is the point (1,8)

Part 3) The equation of the axis of symmetry is x=1

Part 4) The vertex is a minimum

Part 5) The quadratic equation in standard form is y=2x^{2}-4x+10

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

if a > 0 then the parabola open upward (vertex is a minimum)

if a < 0 then the parabola open downward (vertex is a maximum)

The equation of the axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex

so

x=h

In this problem we have

y=2(x-1)^{2}+8 -----> this is the equation in vertex form of a vertical parabola

The value of a=2

so

a>0 then the parabola open upward (vertex is a minimum)

The vertex is the point (1,8)

so

(h,k)=(1,8)

The equation of the axis of symmetry is x=1

The equation of a vertical parabola in standard form is equal to

y=ax^{2}+bx+c

Convert vertex form in standard form

y=2(x-1)^{2}+8

y=2(x^{2}-2x+1)+8

y=2x^{2}-4x+2+8

y=2x^{2}-4x+10

see the attached figure to better understand the problem

7 0
3 years ago
3)A ball is kicked from a height of 2 feet off the ground, after 1 second the ball rea
MArishka [77]

Answer:

y = - 2x + (1/2 38) + 2   = y =  -2x + 19x + 2  at any second  and y = -2x^2 / 2  + 19/2 + 2/2 = <u>- x^2 + 19/2 + 2 </u>=  - x (4) + 19/2(4) + 1 = -4+ 38 + 1 = 35 seconds  

Step-by-step explanation:    We see that 38-2ft = 36ft and y intercept  = 2 and then -2x allows us to represent the starting point 2 as -2 (1) to allow a descend to our back to 0 for y  one we find y intercept we know - x^2  is our simplified equation and an input into this to find the static and slowed descend back to 0  if you keep inputting at 5 and 6 you see the equation speed up   Anyway at (4) substitute = 4 seconds we divide our simplified equation a = -x2 into  a b c and divide each by 2  before working out the<u> </u><u>decline</u> of the equation<u> (as equation still represents all ascending and descending) </u>for the 4th second as the height was <u>already said to be at its max at 38 feet see equation in answer to find 4 as substitute for x </u>

3 0
2 years ago
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