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Paladinen [302]
3 years ago
6

A survey shows that 45% of the respondents pick option A. Given that 50 people replied, what is the standard error of the propor

tion
Mathematics
2 answers:
QveST [7]3 years ago
3 0
The formula for the standard error is this:
σM = σ / √N

where
σM is the standard error
σ is the standard deviation
N is the number of samples

So,
σM = 0.45 / √50
σM = 0.0636 or 6.36%

The standard error is 0.0636
Fantom [35]3 years ago
3 0

Answer:

i got the same answer as the other guy, but the answer choices are:

A.  7.04%  

B. 14.06%

C.  21.09%  

D.  0.07%


Step-by-step explanation:


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Answer:

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Step-by-step explanation:


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Find a factorization of x² + 2x³ + 7x² - 6x + 44, given that<br> −2+i√√7 and 1 - i√/3 are roots.
Levart [38]

A factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

<h3>What are the properties of roots of a polynomial?</h3>
  • The maximum number of roots of a polynomial of degree n is n.
  • For a polynomial with real coefficients, the roots can be real or complex.
  • The complex roots of a polynomial with real coefficients always exist in a pair of conjugate numbers i.e., if a+ib is a root, then a-ib is also a root.

If the roots of the polynomial p(x)=ax^4+bx^3+cx^2+dx+e are r_1,r_2,r_3,r_4, then it can be factorized as p(x)=(x-r_1)(x-r_2)(x-r_3)(x-r_4).

Here, we are to find a factorization of p(x)=x^4+2x^3+7x^2-6x+44. Also, given that -2+i\sqrt{7} and 1-i\sqrt{3} are roots of the polynomial.

Since p(x)=x^4+2x^3+7x^2-6x+44 is a polynomial with real coefficients, so each complex root exists in a pair of conjugates.

Hence, -2-i\sqrt{7} and 1+i\sqrt{3} are also roots of the given polynomial.

Thus, all the four roots of the polynomial p(x)=x^4+2x^3+7x^2-6x+44, are: r_1=-2+i\sqrt{7}, r_2=-2-i\sqrt{7}, r_3=1-i\sqrt{3}, r_4=1+i\sqrt{3}.

So, the polynomial p(x)=x^4+2x^3+7x^2-6x+44 can be factorized as follows:

\{x-(-2+i\sqrt{7})\}\{x-(-2-i\sqrt{7})\}\{x-(1-i\sqrt{3})\}\{x-(1+i\sqrt{3})\}\\=(x+2-i\sqrt{7})(x+2+i\sqrt{7})(x-1+i\sqrt{3})(x-1-i\sqrt{3})\\=\{(x+2)^2+7\}\{(x-1)^2+3\}\hspace{1cm} [\because (a+b)(a-b)=a^2-b^2]\\=(x^2+4x+4+7)(x^2-2x+1+3)\\=(x^2+4x+11)(x^2-2x+4)

Therefore, a factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

To know more about factorization, refer: brainly.com/question/25829061

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1 year ago
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Write the equation in standard form.<br> y - 10=-2(x-8)
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Answer:

2x + y = 26

Step-by-step explanation:

The standard form of a linear equation is   A x + By = C.

Simplify -2(x - 8)

Multiply -2 by -8

y - 10 = -2x + 16

2x + y - 10 = 16

Add 10 to both sides.

Add 16 and 10

Answer= 2x + y = 26

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If CDEF ≅ MNPQ, then EF≅ _____
Anuta_ua [19.1K]
Your answer would be PQ 
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