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tester [92]
2 years ago
11

PLEASEE Solve x=6 4x +y =20

Mathematics
2 answers:
Tanya [424]2 years ago
8 0

Answer: y = -4

Step-by-step explanation:

4 (6) + y = 20

24 + y = 20

-24 -24

y = -4

Stels [109]2 years ago
3 0

Answer:

x = 6

y = -4

Step-by-step explanation:

Comment

You have 2 equations

x = 6

4x + y = 20

You already know what x is from the first equation.

All you need do is put 6 in for x in the second equation.

Solution

x = 6

4*6 + y = 20               Combine what you can on the left

24 + y = 20                Subtract 24 from both sides

24-24+ y = 20-24      Combine

y = - 4

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HEEEEEEEEEEEEEEEEEEEEEEEELLLLLLLLP I BEG U! <br><br> BRAINLIEST FOR FIRST AND CORRECT ANSWER.
Tresset [83]
The answer to this question is 99/4, or 24.75, or 24 3/4.
They are all the same answer


I hope this helps!!!!!! 
3 0
3 years ago
Read 2 more answers
What is the solution to the following equation 4x+3y-z=-6
Alexandra [31]
I think it’s -6/7xyz be my guess
4 0
4 years ago
What are the domain and range of the function f(x)=3/6x+5
devlian [24]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
The number of hurricanes that will hit a certain house in the next ten years is Poisson distributed with mean 4. Each hurricane
bulgar [2K]

Answer:

The variance of total loss is 8000000

Step-by-step explanation:

Let

X \to Number of hurricane

Poisson E(X) = 4

Y \to Loss in each hurricane

Exponential E(Y) = 1000

T \to Total Loss

Required

The variance of the total loss

This is calculated as:

Var(T) = Var(E(T|X)) + E(Var(T|X))

Where:

E(T|X) \to Expected total loss given X hurricanes

And it is calculated as:

E(T|X) = E(Y) *N --- Expected Loss in each hurricane * number of loss

Var(T|X) \to Variance of total loss given X hurricanes

And it is calculated as:

Var(T|X) = Var(Y) * N ---- --- Variance of loss in each hurricane * number of loss

So, we have:

Var(T) = Var(E(T|X)) + E(Var(T|X))

Var(T) = Var(E(Y) * N) + E(Var(Y) * N)

For exponential distribution;

Var(Y) = E(Y)^2

So, we have:

Var(T) = Var(E(Y) * X) + E(E(Y)^2 * X)

Substitute values

Var(T) = Var(1000 * X) + E(1000^2 * X)

Simplify:

Var(T) = Var(1000 * X) + 1000^2E(X)

Using variance formula, we have:

Var(T) = 1000^2Var(X) + 1000^2E(X)

For poission distribution:

Var(X) = E(X)

So, we have:

Var(X) = E(X) = 4

The expression becomes:

Var(T) = 1000^2*4 + 1000^2*4

Var(T) = 1000000*4 + 1000000*4

Var(T) = 4000000 + 4000000

Var(T) = 8000000

3 0
3 years ago
Given: 5x - 6y = 10. Determine the x value when y has a value of 0.
trapecia [35]
Plug Y = 0 in given equation to find X,

5x - 6(0) = 10
5x           = 10
x             =   10/5
x             =    2

Hope this helps!
4 0
4 years ago
Read 2 more answers
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