<span>In order to find the solution, we must solve for 'x' in the initial equation. What we do to one side of the equation to isolate 'x', we must do to the other. If we subtract 5x from both sides were are left with x - 2 = 3. We then add 2 to both sides to completely isolate 'x' and are left with x = 5. This is in the replacement set and is one of the provided solutions, D.</span>
B
my answer has to be at least 20 letters.....
Answer:
10.5 cm
Step-by-step explanation:
A line segment is defined as a part of a line. It is a straight line having two end points. The only difference between a line and line segment is that a line is continuous with indefinite length whereas a line segment has a definite length to it between the two points.
In the figure, the length of the line segment is 10.5 cm (rounded to the nearest tenth).
<h2>
Answer:</h2>
The speed of the commercial jet is
while the speed of the private airplane is ![330mi/h](https://tex.z-dn.net/?f=330mi%2Fh)
<h2>
Step-by-step explanation:</h2>
Let's name the commercial jet as cj and private airplane as pa, so we know the following:
<u>It takes the commercial jet 1.1 hours for the flight, so:</u>
![t_{cj}=1.1h](https://tex.z-dn.net/?f=t_%7Bcj%7D%3D1.1h)
<u>It takes the private airplane 1.8 hours for the flight, so:</u>
![t_{pa}=1.8h](https://tex.z-dn.net/?f=t_%7Bpa%7D%3D1.8h)
<u>The speed of the commercial jet is 210 miles per hour faster than the speed of the private airplane:</u>
Let's name the speed of the commercial jet as
and the speed of the private airplane as
, then:
![v_{cj}=v_{pa}+210](https://tex.z-dn.net/?f=v_%7Bcj%7D%3Dv_%7Bpa%7D%2B210)
From physics we know that:
![v=\frac{d}{t} \\ \\ Where: \\ \\ v: \ speed \\ \\ d: \ distance \\ \\ t: \ time](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%7D%7Bt%7D%20%5C%5C%20%5C%5C%20Where%3A%20%5C%5C%20%5C%5C%20v%3A%20%5C%20speed%20%5C%5C%20%5C%5C%20d%3A%20%5C%20distance%20%5C%5C%20%5C%5C%20t%3A%20%5C%20time)
Since the distance from Denver to phoenix is unique, then:
![d_{cj}=d_{pa}=d](https://tex.z-dn.net/?f=d_%7Bcj%7D%3Dd_%7Bpa%7D%3Dd)
Thus, from the equation
and given the relationship
we have:
![v_{cj}=v_{pa}+210 \\ \\ \frac{d}{t_{cj}}=\frac{d}{t_{pa}}+210 \\ \\ \\ Plug \ in \ t_{cj}=1.1 \ and \ t_{pa}=1.8 \ then: \\ \\ \frac{d}{1.1}=\frac{d}{1.8}+210 \\ \\ Isolating \ d: \\ \\ d(\frac{1}{1.1}-\frac{1}{1.8})=210 \\ \\ \frac{35}{99}d=210 \\ \\ d=\frac{99\times 210}{35} \\ \\ d=594miles](https://tex.z-dn.net/?f=v_%7Bcj%7D%3Dv_%7Bpa%7D%2B210%20%5C%5C%20%5C%5C%20%5Cfrac%7Bd%7D%7Bt_%7Bcj%7D%7D%3D%5Cfrac%7Bd%7D%7Bt_%7Bpa%7D%7D%2B210%20%5C%5C%20%5C%5C%20%5C%5C%20Plug%20%5C%20in%20%5C%20t_%7Bcj%7D%3D1.1%20%5C%20and%20%5C%20t_%7Bpa%7D%3D1.8%20%5C%20then%3A%20%5C%5C%20%5C%5C%20%5Cfrac%7Bd%7D%7B1.1%7D%3D%5Cfrac%7Bd%7D%7B1.8%7D%2B210%20%5C%5C%20%5C%5C%20Isolating%20%5C%20d%3A%20%5C%5C%20%5C%5C%20d%28%5Cfrac%7B1%7D%7B1.1%7D-%5Cfrac%7B1%7D%7B1.8%7D%29%3D210%20%5C%5C%20%5C%5C%20%5Cfrac%7B35%7D%7B99%7Dd%3D210%20%5C%5C%20%5C%5C%20d%3D%5Cfrac%7B99%5Ctimes%20210%7D%7B35%7D%20%5C%5C%20%5C%5C%20d%3D594miles)
Finally, the speeds are:
![\bullet \ v_{cj}=\frac{d}{t_{cj}} \\ \\ v_{cj}=\frac{594}{1.1} \therefore \boxed{v_{cj}=540mi/h} \\ \\ \\ \bullet \ v_{pa}=\frac{d}{t_{pa}} \\ \\ v_{pa}=\frac{594}{1.8} \therefore \boxed{v_{pa}=330mi/h}](https://tex.z-dn.net/?f=%5Cbullet%20%5C%20v_%7Bcj%7D%3D%5Cfrac%7Bd%7D%7Bt_%7Bcj%7D%7D%20%5C%5C%20%5C%5C%20v_%7Bcj%7D%3D%5Cfrac%7B594%7D%7B1.1%7D%20%5Ctherefore%20%5Cboxed%7Bv_%7Bcj%7D%3D540mi%2Fh%7D%20%5C%5C%20%5C%5C%20%5C%5C%20%5Cbullet%20%5C%20v_%7Bpa%7D%3D%5Cfrac%7Bd%7D%7Bt_%7Bpa%7D%7D%20%5C%5C%20%5C%5C%20v_%7Bpa%7D%3D%5Cfrac%7B594%7D%7B1.8%7D%20%5Ctherefore%20%5Cboxed%7Bv_%7Bpa%7D%3D330mi%2Fh%7D)
Answer: 8=8/3
Step-by-step explanation: