Answer is in the file below
tinyurl.com/wpazsebu
Find the line that is normal to the parabola at the given point
remember that normal means perpendicular
perpendicular lines have slopes that multiply to -1
we can use point slope form to write the equation of the line since we are given the point (1,0)
we just need the slope
take derivitive
y'=1-2x
at x=1
y'=1-2(1)
y'=1-2
y'=-1
the slope is -1
the perpendicular of that slope is what number we can multiply to get -1
-1 times what=-1?
what=1
duh
so
point (1,0) and slope 1
y-0=1(x-1)
y=x-1 is da equation
solve for where y=x-1 and y=x-x² intersect
set equatl to each other since equal y
x-1=x-x²
x²-1=0
factor difference of 2 perfect squares
(x-1)(x+1)=0
set to zero
x-1=0
x=1
we got this point already
x+1=0
x=-1
sub back
y=-1-(-1)²
y=-1-(1)
y=-1-1
y=-2
it intersects at (-1,-2)
A coefficient is a number that is attached to a term.
For example:
3x² - 5x + 6 = 0
The coefficient of x² is 3.
The coefficient of x = -5.
Hope this explains it.
Infinitely many? Arrows indicate that the graph goes on continuously without a stopping point, even in parabolas.
Answer:
x > 5
Step-by-step explanation:
Given that:
= -2(3x + 2) > -8x + 6
(negative sign before bracket will alter the internal signs when multiplied by each term)
= -6x - 4 > -8x +6
Taking x terms on left side and other constants on right side
= -6x + 8x > 6 +4
Signs will be changer for transferred terms
= 2x > 10
By Dividing both sides 2 we get
=x > 10/2
= x >5
