Answer:
P-value is lesser in the case when n = 500.
Step-by-step explanation:
The formula for z-test statistic can be written as

here, μ = mean
σ= standard deviation, n= sample size, x= variable.
From the relation we can clearly observe that n is directly proportional to test statistic. Thus, as the value of n increases the corresponding test statistic value also increases.
We can also observe that as the test statistic's numerical value increases it is more likely to go into rejection region or in other words its P-value decreases.
Now, for first case when our n is 50 we will have a relatively low chance of accurately representing the population compared to the case when n= 500. Therefore, the P-value will be lesser in the case when n = 500.
Sally can paint a house in 4 hours; Which means in 1 hour she can paint 1/4th of the house.
John can paint the same house in 6 hours. Which means in 1 hour she can paint 1/6th of the house.
Together in 1 hour they can paint: - 1/4 + 1/6 = 5/12th of the house.
Total Hours for painting the house together will be 12/5 = 2.4 Hours.
So the answer is 2 hours and 24 minutes
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Answer:
16
Step-by-step explanation:
Answer:
67
Step-by-step explanation:
Solution :
The null and alternative hypothesis is given by


Assume that the level of significance, α = 0.05
The t-test statistics is, t = 1.484
Degree of freedom :
df = n - 1
= 14 - 1
= 13
The P-value is given by
P-value = 2P (T>|t|)
= 2P(T>|1.484|)
= 2P(T>1.484)
= 2(=T.DIST.RT(1.484,13))
= 0.05