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erik [133]
3 years ago
9

The price of a stock decreased by 60 cents one week, decreased 10 cents the next week, and decreased another 20 cents the follow

ing week. What is the average change in the price of the stock over the three weeks?
Mathematics
1 answer:
Arturiano [62]3 years ago
6 0
<h2>Answer:</h2>

The average change in the price of stock over the three weeks is:

       It decreased by 30 cents per week.

<h2>Step-by-step explanation:</h2>

It is given that the price of stocks decreased by 60 cents one week.

It decreased by 10 cents in the next week

and 20 in the third week.

Hence, the average rate of change is calculated as the ratio of the sum of the change in the three weeks divided by the number of weeks i.e. 3.

Hence,

\text{Rate\ of\ change}=\dfrac{-60-10-20}{3}\\\\\\\text{Rate\ of\ change}=\dfrac{-90}{3}=-30

As the average rate of change is negative this means that the price of the stocks decreased.

and it decreased by a rate of 30 cents per week.

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ICE Princess25 [194]
Let x be the unknown number. The equation is going to be 7/28=25/x, now we cross multiply. 7*x=25*28, 7x=700, divide both sides by 7 and you should get 100, So, x=100 and 7/28=25/100
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Answer:

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Step-by-step explanation:

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2 years ago
Find the average rate of change for f(x) = x2 + 9x + 18 from x = −10 to x = 10. A) 3 B) 7 C) 9 D) 11
Sergeeva-Olga [200]

Answer:

C

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [ a, b ] = [ - 10, 10 ], thus

f(b) = f(10) = 10² + 9(10) + 18 = 100 + 90 + 18 = 208

f(a) = f(- 10) = (- 10)² + 9(- 10) + 18 = 100 - 90 + 18 = 28, thus

average rate of change = \frac{208-28}{10-(-10)} = \frac{180}{20} = 9

3 0
3 years ago
Given that the expression 2x^3 + mx^2 + nx + c leaves the same remainder when divided by x -2 or by x+1 I prove that m+n =-6
Alla [95]

Given:

The expression is:

2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1.

To prove:

m+n=-6

Solution:

Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).

Let the given polynomial is:

P(x)=2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that

P(2)=P(-1)              ...(i)

Substituting x=-1 in the given polynomial.

P(-1)=2(-1)^3+m(-1)^2+n(-1)+c

P(-1)=-2+m-n+c

Substituting x=2 in the given polynomial.

P(2)=2(2)^3+m(2)^2+n(2)+c

P(2)=2(8)+m(4)+2n+c

P(2)=16+4m+2n+c

Now, substitute the values of P(2) and P(-1) in (i), we get

16+4m+2n+c=-2+m-n+c

16+4m+2n+c+2-m+n-c=0

18+3m+3n=0

3m+3n=-18

Divide both sides by 3.

\dfrac{3m+3n}{3}=\dfrac{-18}{3}

m+n=-6

Hence proved.

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3 years ago
How does the value of b affect the graph of y=my+b?
dezoksy [38]
B is your y intercept on the graph.
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