Question

Describe the solution(s) to 9x² - 36x + 36 = 0 by just determining the radicand. Show your work. (10 points) Part B: Describe the solution (s) to x²-x + 4 = 0 by just determining the radicand. Show your work. (10) points) Part C: Solve 4x² + 23 – 35 using an - appropriate method. Show the steps of your work and explain why you chose the method used​

Answer 1

The solution to the equations are:

• 9x² - 36x + 36 = 0 has two equal real solutions
• x² - x + 4 = 0 has no real solutions
• The factored expression of 4x² + 23 – 35 is 4(x² -3)

Part A: Describe the solution

The equation is given as:

$9x\² - 36x + 36 = 0$

The above equation is a quadratic equation which can be represented as:

$ax\² + bx + c = 0$

The discriminant (d) is calculated as:

$d = b\² - 4ac$

So, we have:

$d = (-36)\² - 4 * 9 * 36$

$d = 0$

A discriminant of 0 means that the equation has two equal real solutions

Hence, 9x² - 36x + 36 = 0 has two equal real solutions

Part B: Describe the solution

The equation is given as:

$x\² - x + 4 = 0$

The above equation can be represented as:

$ax\² + bx + c = 0$

The discriminant (d) is calculated as:

$d = b\² - 4ac$

So, we have:

$d = (-1)\² - 4 * 1 * 4$

$d = -15$

A discriminant of -15 means that the equation has no real solutions

Hence, x² - x + 4 = 0 has no real solutions

Part C: The solution to the expression

We have:

$4x\² + 23 - 35$

Evaluate the difference

$4x\² -12$

Factor out 4

$4(x\² -3)$

Hence, the factored expression of 4x² + 23 – 35 is 4(x² -3)

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