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jasenka [17]
2 years ago
13

Solve the following quadratic by

Mathematics
1 answer:
serious [3.7K]2 years ago
5 0

Answer:

x = -2+- sqrt(6)

Step-by-step explanation:

Using completing the square, let x^2+4x-2 = 0 and solve the steps to get the answerx^2 + 4x - 2 =0

add 2 to both sides to get x^2 + 4x = 2

then add 4 to both sides to get x^2 + 4x + 4 = 6

Get the left hand side to the square formate: (x+2)^2 = 6

then simplify x+2 = sqrt(6) or x+2 = -sqrt(6)

so x = sqrt(6) - 2 or x = -sqrt(6) -2

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Step-by-step explanation:

Use a Table of Values to Graph the Equation y =3x+1. y=3x+1 y = 3 x + 1. Substitute −2 - 2 for x x and find the result for y y . y=3(−2)+1 y

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Which relationship is always true for the angles x, y, and z of triangle MNP?
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3 years ago
Can someone please explain to me how to solve these types of equations? I'm supposed to solve for x in 4^(-5x-6)=4^(9x+4)
Ksenya-84 [330]

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Step-by-step explanation:

8 0
3 years ago
The sum of the first three terms of a sequence is 6 and the fourth term is 16
Sati [7]

Answer:

              a₁ = -5, d = 7,  a₂ = 2, a₃ = 9, a₄ = 16

equation of sequence:    \boxed{\bold{a_n=7n-12}}

Step-by-step explanation:

a₁ + a₂ + a₃ = 6    

a₁ + a₁ + d + a₁ + 2d = 6

3a₁ + 3d = 6

a₁ + d= 2     ⇒ a₁ = 2 - d

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equation of arithmetic sequence:

a_n=a_1+d(n-1)\\\\a_n=-5+7(n-1)\\\\\underline{a_n=7n-12}

6 0
3 years ago
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