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expeople1 [14]
3 years ago
14

Suppose we have three urns, namely, A B and C. A has 3 black balls and 7 white balls. B has 7 black balls and 13 white balls. C

has 12 black balls and 8 white balls. We first choose one urn from A, B and C. Then we randomly pick up two balls from that urn without replacement. Let Ai, i 1,2,3 denote the event that the urn we choose is A, B and C respectively. Suppose P(A1): P(A2): P(A3) =1:2:2. Compute :
(a) The probability that the first ball is black.
(b) The probability that the first ball is black given that the second ball is white.
Mathematics
1 answer:
professor190 [17]3 years ago
8 0

Answer:

a. 11/25

b. 11/25

Step-by-step explanation:

We proceed as follows;

From the question, we have the following information;

Three urns A, B and C contains ( 3 black balls 7 white balls), (7 black balls and 13 white balls) and (12 black balls and 8 white balls) respectively.

Now,

Since events of choosing urn A, B and C are denoted by Ai , i=1, 2, 3

Then , P(A1 + P(A2) +P(A3) =1 ....(1)

And P(A1):P(A2):P(A3) = 1: 2: 2 (given) ....(2)

Let P(A1) = x, then using equation (2)

P(A2) = 2x and P(A3) = 2x

(from the ratio given in the question)

Substituting these values in equation (1), we get

x+ 2x + 2x =1

Or 5x =1

Or x =1/5

So, P(A1) =x =1/5 , ....(3)

P(A2) = 2x= 2/5 and ....(4)

P(A3) = 2x= 2/5 ...(5)

Also urns A, B and C has total balls = 10, 20 , 20 respectively.

Now, if we choose one urn and then pick up 2 balls randomly then;

(a) Probability that the first ball is black

=P(A1)×P(Back ball from urn A) +P(A2)×P(Black ball from urn B) + P(A3)×P(Black ball from urn C)

= (1/5)×(3/10) + (2/5)×(7/20) + (2/5)×(12/20)

= (3/50) + (7/50) + (12/50)

=22/50

=11/25

(b) The Probability that the first ball is black given that the second ball is white is same as the probability that first ball is black (11/25). This is because the event of picking of first ball is independent of the event of picking of second ball.

Although the event picking of the second ball is dependent on the event of picking the first ball.

Hence, probability that the first ball is black given that the second ball is white is 11/25

​​

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Lines a and b are parallel.
VashaNatasha [74]
I have added a screenshot with the complete question along with a diagram representing the scenario.

<u><em>Answer:</em></u>
s = 22°

<u><em>Explanation:</em></u>
<u>1- getting the top right angle of line B:</u>
We are given that:
the top right angle of line A = 158°
Since lines A and B are parallel, therefore, the top right angle of line A and the top right angle of line B are corresponding angles which means that they are equal
This means that:
<u>Top right angle of line B = 158°</u>

<u>2- getting the value of s:</u>
Now, taking a look at line B, we can note that:
angle s and the top right angle form a straight angle. This means that the sum of these two angles is 180°
Therefore:
180 = s + 158
s = 180 - 158
<u>s = 22°</u>

Hope this helps :)

8 0
3 years ago
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