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2 years ago

Need help with questions 32-33

Mathematics

2 answers:

nirvana33 [79]2 years ago

7 0

I will assume 'xx' as one variable, in other words, it isn't equal to x²:

⇒ its just 'xx'

For question 32, let's solve:

$\frac{xx}{9}=\frac{2}{3} \\3xx=9*2\\3xx = 18\\xx=6$ --> choice (c)

For question 33, let's solve:

$\frac{3}{xx} =\frac{5}{xx-2}\\3(xx-2)=5*xx\\3xx-6=5xx\\5xx-3xx=-6\\2xx=-6\\xx=-3$ --> choice (b)

Answers:

For question 32: (c)
For question 33: (b)

Hope that helps!

velikii [3]2 years ago

4 0

The answer for 32 is 6 and the answer for 33 is -3

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Step-by-step explanation:

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