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hichkok12 [17]
3 years ago
15

A real estate agent has surveyed houses in twenty nearby zip codes in an attempt to put together a comparison for a new property

that she would like to put on the market. The 1057 houses she surveyed have a mean price of ​$169 comma 400​, with a standard deviation of $ 68 comma 438. The mean living area is 2058 sq​ ft, with a standard deviation of 790 sq ft. Which is more​ unusual, a house in that market that sells for ​$300 comma 000 or a house that has 3000 sq ft of living​ area? Explain. Choose the correct answer below. The house that sells for ​$300 comma 000 has a​ z-score of nothing and the house with 3000 sq ft has a​ z-score of nothing. ​Thus, a house in that market that ▼ sells for $ 300 comma 000 has 3000 sq ft of living area is more unusual than a house that ▼ sells for $ 300 comma 000 has 3000 sq ft of living area .
Mathematics
1 answer:
gladu [14]3 years ago
5 0

Answer:

A a house in that market that sells for ​$300,000 is unusual.

Step-by-step explanation:

Let the random variable <em>X</em> denote the price of a house and the random variable <em>Y</em> denote the living area of a house.

The number of houses surveyed by the real estate agent is, <em>n</em> = 1057.

Assume that both the random  variables, <em>X </em>and <em>Y</em> are approximately normally distributed.

That is,

X\sim N(\$169400,\ \$68438)\\\\Y\sim N(2058\ \text{sq. ft.},\ 790\ \text{sq. ft.})

To compute the probability of a Normal distribution we first need to convert the raw scores to <em>z</em>-scores.

z=\frac{\text{Raw score}-\mu}{\sigma}

A <em>z</em>-score higher than 1.96 and lower than -1.96 are considered unusual. The values having these <em>z</em>-scores are considered as outliers.

(1)

Compute the <em>z</em>-score for <em>X</em> = 300000 as follows:

z=\frac{X-\mu}{\sigma}\\\\=\frac{300000-169400}{68438}\\\\=2.70

(2)

Compute the <em>z</em>-score for <em>Y</em> = 3000 as follows:

z=\frac{Y-\mu}{\sigma}\\\\=\frac{3000-2058}{790}\\\\=1.19

The <em>z</em>-score for a house in that market that sells for ​$300,000 is more than 1.96.

This implies, that the price $300,000 is unusually high.

The complete statement is:

The house that sells for ​$300 comma 000 has a​ z-score of <u>2.70</u> and the house with 3000 sq ft has a​ z-score of <u>1.19</u>.

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