Let z be any number (like x would be)
if we set z equal to 2x-6y, then we get z = 2x-6y
The system
2x-6y = 8
2x-6 = 3
turns into this new system
z = 8
z = 3
but z is a single number. It can't be both 8 and 3 at the same time. So there are no solutions
do: first of first bracket x first of 2nd bracket
+( first of 1st bracket x 2nd of 2nd bracket)
+(2nd of 1st bracket x 1st of 2nd bracket)
+ (2nd of 1st bracket x 2nd of 2nd bracket)
== 10n -16n +20n+32= 14n+32
The total space in the parking lot is 1600 cars
It is mentioned that
parts of this parking is filled
Now we are required to find what is the three-fourths part of 1600
To find it we multiply
times 1600

= 
=
= 1200 cars
Hence 1200 cars fills the three-fourths of the car parking lot that has a capacity of 1600 cars